[Solved] Python Code Fails

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The thing is that range and xrange are written in C, hence they are prone to overflows. You need to write your own number generator to surpass the limit of C long.

def my_range(end):
    start = 0
    while start < end:
        yield start
        start +=1 


def conforms(k,s):
    k = k + 1
    if s.find("0" * k) == -1 and s.find("1" * k) == -1:
        return True
    else:
        return False


def brute(n,k,s):
    min_val = n + 1
    min_str = ""
    desired = long(s,2)
    for i in my_range(2 ** n):
        xor = desired ^ i # gives number of bit changes
        i_rep = bin(i)[2:].zfill(n) # pad the binary representation with 0s - for conforms()
        one_count = bin(xor).count('1')
        if one_count < min_val and conforms(k, i_rep):
            min_val = bin(xor).count('1')
            min_str = i_rep
    return (min_val,min_str)


T = 1
for i in range(T):
    words = [100, 1]
    start="00000001"
    sol = brute(words[0], words[1], start)
    print sol[0]
    print sol[1]

12

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solved Python Code Fails