[Solved] How to reformat code to output properly?

by 


#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// dst needs to at least strlen(src)*2+1 in size.
void encode(char* dst, const char* src) {
    while (1) {
       char ch = *src;
       if (!ch) {
          *dst = 0;
          return;
       }

       size_t count = 1;
       while (*(++src) == ch)
          ++count;

       *(dst++) = ch;
       dst += sprintf(dst, "%zu", count);
    }
}

int main(int argc, char** argv) {
   if (argc != 2) {
      fprintf(stderr, "usage\n");
      return 1;
   }

   const char* src = argv[1];
   char* dst = malloc(strlen(src)*2+1);
   encode(dst, src);
   printf("%s\n", dst);
   free(dst);
   return 0;
}


$ gcc -Wall -Wextra -pedantic -std=c99 -o a a.c

$ ./a aabccccccggeeecccccd
a2b1c6g2e3c5d1

$ ./a abc
a1b1c1

7

solved How to reformat code to output properly?