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Best way I think
double NthRoot(double value, double degree)
{
return pow(value, (double)(1 / degree));
}
From here.
0
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solved n-th root of a number [closed]
[ad_1]
Best way I think
double NthRoot(double value, double degree)
{
return pow(value, (double)(1 / degree));
}
From here.
0
[ad_2]
solved n-th root of a number [closed]