[Solved] Too few arguments in call [closed]

by


Lets break 

pow(payMent = loanAmount * monthlyIntrest / (1 - (1 + monthlyIntrest),-loanDuration));

down a bit.

payMent = loanAmount * monthlyIntrest / (1 - (1 + monthlyIntrest),-loanDuration)

is one argument. The comma that should split it into two arguments is inside the brackets. Likely you meant 

payMent = loanAmount * monthlyIntrest / (1 - (1 + monthlyIntrest)), -loanDuration

but even this is dodgy. You can put the assignment inside the function call, but why? You gain nothing and lose job opportunities for writing needlessly cryptic-as-smurf code.

The sane programmer writes

payMent = loanAmount * monthlyIntrest / (1 - (1 + monthlyIntrest));
pow(payMent,-loanDuration);

But 

(1 - (1 + monthlyIntrest))

doesn’t quite look right. It resolves down to monthlyIntrest, so it’s very likely there is at least one additional transcription error typing in the formula.

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solved Too few arguments in call [closed]