[Solved] Function in C language. + Arrays [closed]

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I don’t want to do your homework for you. However, I know that it sometimes helps to see a working example. This is a really super rudimentary example, but it should help you to understand the logic behind such a problem.

Please study this answer, rather than just submitting it as correct. You will only gain insight by learning. 

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>


const int asc = 1;
const int desc = 0;

int array_asc[11] = {1,2,3,4,5,6,7,8,9,10};
int array_desc[11] = {10,9,8,7,6,5,4,3,2,1};
int array_rand[11] = {7,3,8,4,5,1,6,2,4,4};

int order_check[2] = {0, 0};

int check_order(int* array){

    if(array[0] < (array[1])){
        order_check[0] = asc;
    } else if (array[1] < (array[0])){
        order_check[0] = desc;
    } else {
        return 1;
    }
    return 0;
}

int check_array(int* array, int* check){


    switch(check[0]){

        case 1: 
        for(int i = array[0]; i < array[9]; i ++){
            if(array[i] < (array[i+1])){
                continue;
            } else {
                return i + 1;
            }
        }; break;

        case 0: 
        for(int i = 0; i < 9; i++){
            if(array[i] > (array[i+1])){
                continue;
            } else {
                return i + 1;
            }
        }; break;
    }
    return 0;
}

int main(int argc, char** argv) {

    int ret;

    if(check_order(array_rand) == 0){
        if(ret = check_array(array_rand, order_check)){
            printf("Order breaks at index %d", ret);
        } else {
            printf("Array is in perfect order");
        }
    } else {
        printf("Array is not in order.\n");
    }    
    return (EXIT_SUCCESS);
}

solved Function in C language. + Arrays [closed]