[Solved] Programming java to determine a symmetrical word [closed]

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You can use the modulo operator to determine whether the word has an even or odd number of letters (% in java)

if ( (word.length % 2) == 1 ) {
    //odd
}
else {
    //even
}

then just split the string in half and compare the reverse of the end with the front

int halfLength = word.length / 2;
String firstHalf = word.substring(0, halfLength);
String secondHalf = word.substring(halfLength, word.length);
if (firstHalf.equals(secondHalf.reverse()) {
    //they match
}

something like this should work, I just wrote it up real quick, might need to make a few changes to match java syntax.

2

solved Programming java to determine a symmetrical word [closed]