[Solved] Problems with the “+” and “-” operators

Question

If you change line 8 to:

array[i+1] = 3;

then the number 3 will go all the way to the end of the array (well, beyond the end of the array and I’ll be damned to find out what Javascript does then!). This is because the loop traverses the array in increasing order and the position i+1 will be checked right next.

On the other hand, with your current line 8, number 3 goes one position backwards (which has already been checked), so it doesn’t go all the way to the beginning of the array, just one position. If you want it to go to all the way in the same fashion, you should reverse the loop (make it traverse the array in descending order of the position i).

Accepted Answer

If you change line 8 to:

array[i+1] = 3;

then the number 3 will go all the way to the end of the array (well, beyond the end of the array and I’ll be damned to find out what Javascript does then!). This is because the loop traverses the array in increasing order and the position i+1 will be checked right next.

On the other hand, with your current line 8, number 3 goes one position backwards (which has already been checked), so it doesn’t go all the way to the beginning of the array, just one position. If you want it to go to all the way in the same fashion, you should reverse the loop (make it traverse the array in descending order of the position i).