[Solved] No error/warning for multiple cout in one statement

Question

Why should the compiler warn you about something that is perfectly legal? You are instructing the program to output the content of cout, which is legal, and will work.

I am not sure how the operator << is defined for cout, but printing its address would be my expectation, so something like 0x489944 (or longer) seems just right.

With the 5 and the 6 around it, your output seems correct: 5+0x489944+6 = 50x4899446

Accepted Answer

Why should the compiler warn you about something that is perfectly legal? You are instructing the program to output the content of cout, which is legal, and will work.

I am not sure how the operator << is defined for cout, but printing its address would be my expectation, so something like 0x489944 (or longer) seems just right.

With the 5 and the 6 around it, your output seems correct: 5+0x489944+6 = 50x4899446