[Solved] C# process parameter invalid while running link86.exe

Question

Looking at the Perl part of the question:

open( FILE "link86 ^& < $tempfn|" ) || die "Could not run link86: $!\n";

This is a syntax error. FILE is a bareword filehandle. You need a comma after that for the next argument to open. So, the line should be:

open( FILE, "link86 ^& < $tempfn|" ) || die "Could not run link86: $!\n";

The second argument is a command for the shell to execute. The trailing pipe indicates that the output of the command will be piped to your program via the FILE filehandle.

^& will be interpreted by the shell executing this program. In this case, I am assuming the shell is cmd.exe. ^ is the escape character in cmd.exe. Therefore, it causes the following & to be interpreted as a literal character. (See also, Everyone quotes command line arguments the wrong way: “When cmd transforms a command line and sees a ^, it ignores the ^ character itself and copies the next character to the new command line literally …”)

I am not exactly sure what it does, but it seems to basically execute link86 using the contents of whatever filename is in $tempfn.

while( <LINK> )
{
    print; # what does the print without parameters do?
    if( /^(EXCEPTION|ERROR)/i ) 
    {
        $abflag = 1;
    }
    print $dlogH "\nabort Flag:  $abflag\n";
}

This reads from the LINK bareword filehandle. Each line is stored in $_, and then printed. Without arguments, print prints the contents of $_ to the currently selected output filehandle (most likely STDOUT).

If the line contains either EXCEPTION or ERROR, it sets the abort flag. For each line read from LINK, it prints the value of abort flag. Once set, the abort flag remains set.

Accepted Answer