[Solved] Why this code gives error? It uses parenthesis in multi line macros.I found this on an article in GeeksforGeeks

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Using clang, the code actually compiles, but it gives some warnings. The warnings are generated because of the parenthesis and braces in the macro definition, or – to be more exact – because of the lack of braces in the if-else statement. You can rewrite the code to the following form:

#include <stdio.h>

#define MACRO(num, str) \
        printf("%d", num);\
        printf(" is");\
        printf(" %s number", str);\
        printf("\n");

int main(void)
{
    int num;

    printf("Enter a number: ");
    scanf("%d", &num);

    if (num & 1)
    {
        MACRO(num, "Odd");
    }
    else
    {
        MACRO(num, "Even");
    }
    return 0;
}

You can further simplify your code to:

#include <stdio.h>

#define MACRO(num, str) printf("%d is %s number\n", num, str);

int main(void)
{
    int num;

    printf("Enter a number: ");
    scanf("%d", &num);

    if (num & 1)
    {
        MACRO(num, "Odd");
    }
    else
    {
        MACRO(num, "Even");
    }
    return 0;
}

solved Why this code gives error? It uses parenthesis in multi line macros.I found this on an article in GeeksforGeeks