Like this: var tr = “”; var totalAmount = “”; var total = 0; //this your total var footerTr = “”; for(var i=1; i<=31; i++){ tr += `<tr> <td>${i}</td> <td>${i*2}</td> </tr>`; totalAmount += `${i*2}+`; total += i*2; //this your total } totalAmount = totalAmount.substring(0, totalAmount.length – 1); // remove last plus totalAmount += ‘=’+total; footerTr … Read more
test2.hpp and test.hpp both #include test1.hpp. If the scope of test1_hpp is the whole application, as far as I understand, there can only one include test1.hpp success. Because once included, test1_hpp is defined. The compiler works on translation units (think: individual .cpp files) not the whole application (think: executable). What you call “the scope of … Read more
function r(s) { var txt = “”; for(var i = s.length – 1; i >= 0; i–) { txt += s[i]; } return txt; } var mathex = “2+5-7%8”; alert(r(mathex)); solved How to reverse a mathematical expression saved as a string in JavaScript?
The second column is binary. So one way would be to change it to logical vector, subset the values that correspond to ‘ON’ and ‘OFF’ (i.e. 1 and 0), get the difference of the sum of both and multiply with 40. 40*(sum(ccmix[,1][!!ccmix[,2]]) – sum(ccmix[,1][!ccmix[,2]])) The negate function (!) converts 0 to TRUE and 1 to … Read more
Loads of bugs in the old code. Here’s a fixed plnkr: http://plnkr.co/edit/NN0eXFg87Ys2E3jjYQSu?p=preview The problem mostly was that you didn’t assign your receive function properly to the scope. It must be done like so: $scope.receive = function() { Your code was like $scope.receive(function() { solved Angular and $q: strangely, nothing is working at all
The SQL query would be $sql = “SELECT t1.user_id FROM table1 AS t1 JOIN table2 AS t2 ON t2.area_id = 3 WHERE t1.cat_id = 11” $this->query($sql); See here for the documentation 2 solved Selecting two columns from different tables in one result using MySQL [closed]
Just create another UIView, add the image inside it and add it as a subview below your view. Than simply animate the frame property of the image. Not sure if this is what you need, but your question is too brief, so is my answer. solved How to make backgroundimage move in Swift iOS [closed]
In my comment I incorrectly remembered the name of the argument for changing the direction of an order result. The fix is simply to use the correct name: > df[ order(rowSums(is.na(df)), decreasing=TRUE), ] x y z v 4 NA NA NA NA 3 6 NA NA NA 6 NA 18 130 NA 10 NA 17 … Read more
= is used to assign a value to a variable, e.g. $foo = ‘bar’ There are some advanced ways to assign variables in Puppet 4, but generally speaking whenever it’s a $variable on the left hand side of the expression, add no comma and always use =. Further variable assignments are simply separated by new … Read more
There is no need to use javascript or keyframes to do that. I feel like your codepen is complicated for not much! Here is your code, modified, with my comments: body { font-family: sans-serif; } .btn-square { width: 100px; height: 100px; background-color: blue; transition: background-color 1s; /* Added */ } .close { position: relative; display: … Read more
Yes, when you say point3 = (char*)point You are converting the integer pointer point to a character pointer point3. point is designed for pointing at whole integers (which of course are multibyte quantities), while point3 can point at individual bytes. So now point3 points at the individual bytes that point points to, or in other … Read more
Why not wrap each set of letters (word) in its own div? Not sure what you’re trying to achieve really, give us a bit more to go on. EDIT. Added code example after, for clarity. <div> <span>w</span> <span>o</span> <span>r</span> <span>d</span> </div> <div> <span>p</span> <span>l</span> <span>a</span> <span>y</span> </div> 2 solved How to center multiple divs in … Read more
a.) In the above code, I am not sure what (DateTime?) startDate means? This is saying cast startDate to a DateTime? object. startDate might be a DateTime and for purposes of this for loop, it’s being cast to a nullable DateTime (DateTime?) b.) scorecardMonths on the very last line… sees to be some object.. Agreed, … Read more
How is it possible that the language a^n b^2n is regular if and only if it was finite such that 100 => n <= 0? [closed] solved How is it possible that the language a^n b^2n is regular if and only if it was finite such that 100 => n
I would: char loop=’y’; while(loop == ‘y’) { //Do your stuff here printf(“do you want to loop? (y/n) “); scanf(” %c”, &loop); if(loop != ‘y’) loop=’n’; } /A 1 solved In C Programming, How do I use a loop to ask user if they want to continue?