{"id":9823,"date":"2022-09-20T22:34:10","date_gmt":"2022-09-20T17:04:10","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-get-sumcol2-as-somenamecol2col3-sumcol2-as-somename1-for-the-some-date\/"},"modified":"2022-09-20T22:34:10","modified_gmt":"2022-09-20T17:04:10","slug":"solved-how-to-get-sumcol2-as-somenamecol2col3-sumcol2-as-somename1-for-the-some-date","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-get-sumcol2-as-somenamecol2col3-sumcol2-as-somename1-for-the-some-date\/","title":{"rendered":"[Solved] how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-29029299\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"29029299\" data-parentid=\"29028587\" data-score=\"0\" data-position-on-page=\"2\" data-highest-scored=\"0\" data-question-has-accepted-highest-score=\"0\" itemprop=\"suggestedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>You can achieve what you&#8217;re after like below:<\/p>\n<pre><code>CREATE TABLE SampleTable\n    ([col1] varchar(1), [col2] int, [col3] int, [date] varchar(16))\n;\n\nINSERT INTO SampleTable\n    ([col1], [col2], [col3], [date])\nVALUES\n    ('a', 11, 0, '3\/6\/2015:0:00:00'),\n    ('b', 5, 4, '3\/6\/2015:0:00:00'),\n    ('c', 5, 5, '3\/6\/2015:0:00:00'),\n    ('d', 3, 0, '3\/6\/2015:0:00:00'),\n    ('e', 21, 21, '3\/6\/2015:0:00:00')\n;\n\nSELECT t2.SumCol2, \n       sum(t1.col2 * t1.col3) \/ (t2.SumCol2 * 1.0) AS CalculatedColumn, \n       t1.[date] AS [Date]\nFROM SampleTable t1\nINNER JOIN (\n    SELECT SUM(col2) AS SumCol2, [Date] \n    FROM SampleTable \n    GROUP BY [date]) AS t2 ON t1.[date] = t2.[date]\nGROUP BY t2.SumCol2, t1.[date]\n<\/code><\/pre>\n<p>However this produces output that doesn&#8217;t match yours, due to a rounding issue:<\/p>\n<pre><code>SumCol2  CalculatedColumn   Date\n--------------------------------------------\n45       10.80              3\/6\/2015:0:00:00\n<\/code><\/pre>\n<p>But looking at your figures, I think my output is correct:<\/p>\n<pre><code>11 * 0   = 0\n5  * 4   = 20\n5  * 5   = 25 \n3  * 0   = 0 \n21 * 21  = 441\n==================\n45       \/ 486   =  10.8\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] You can achieve what you&#8217;re after like below: CREATE TABLE SampleTable ([col1] varchar(1), [col2] int, [col3] int, [date] varchar(16)) ; INSERT INTO SampleTable ([col1], [col2], [col3], [date]) VALUES (&#8216;a&#8217;, 11, 0, &#8216;3\/6\/2015:0:00:00&#8217;), (&#8216;b&#8217;, 5, 4, &#8216;3\/6\/2015:0:00:00&#8217;), (&#8216;c&#8217;, 5, 5, &#8216;3\/6\/2015:0:00:00&#8217;), (&#8216;d&#8217;, 3, 0, &#8216;3\/6\/2015:0:00:00&#8217;), (&#8216;e&#8217;, 21, 21, &#8216;3\/6\/2015:0:00:00&#8217;) ; SELECT t2.SumCol2, sum(t1.col2 * t1.col3) &#8230; <a title=\"[Solved] how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-get-sumcol2-as-somenamecol2col3-sumcol2-as-somename1-for-the-some-date\/\" aria-label=\"More on [Solved] how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[341,500,501],"class_list":["post-9823","post","type-post","status-publish","format-standard","hentry","category-solved","tag-sql","tag-sql-server","tag-sql-server-2008"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-get-sumcol2-as-somenamecol2col3-sumcol2-as-somename1-for-the-some-date\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You can achieve what you&#8217;re after like below: CREATE TABLE SampleTable ([col1] varchar(1), [col2] int, [col3] int, [date] varchar(16)) ; INSERT INTO SampleTable ([col1], [col2], [col3], [date]) VALUES (&#039;a&#039;, 11, 0, &#039;3\/6\/2015:0:00:00&#039;), (&#039;b&#039;, 5, 4, &#039;3\/6\/2015:0:00:00&#039;), (&#039;c&#039;, 5, 5, &#039;3\/6\/2015:0:00:00&#039;), (&#039;d&#039;, 3, 0, &#039;3\/6\/2015:0:00:00&#039;), (&#039;e&#039;, 21, 21, &#039;3\/6\/2015:0:00:00&#039;) ; SELECT t2.SumCol2, sum(t1.col2 * t1.col3) ... 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JassWeb","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/jassweb.com\/solved\/solved-how-to-get-sumcol2-as-somenamecol2col3-sumcol2-as-somename1-for-the-some-date\/","og_locale":"en_US","og_type":"article","og_title":"[Solved] how to get sum(col2) as somename,(col2*col3)\/Sum(col2) as somename1 for the some date - JassWeb","og_description":"[ad_1] You can achieve what you&#8217;re after like below: CREATE TABLE SampleTable ([col1] varchar(1), [col2] int, [col3] int, [date] varchar(16)) ; INSERT INTO SampleTable ([col1], [col2], [col3], [date]) VALUES ('a', 11, 0, '3\/6\/2015:0:00:00'), ('b', 5, 4, '3\/6\/2015:0:00:00'), ('c', 5, 5, '3\/6\/2015:0:00:00'), ('d', 3, 0, '3\/6\/2015:0:00:00'), ('e', 21, 21, '3\/6\/2015:0:00:00') ; SELECT t2.SumCol2, sum(t1.col2 * t1.col3) ... 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