{"id":8674,"date":"2022-09-14T22:27:30","date_gmt":"2022-09-14T16:57:30","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-need-to-show-costs-for-last-6-months-on-complicated-sub-queries\/"},"modified":"2022-09-14T22:27:30","modified_gmt":"2022-09-14T16:57:30","slug":"solved-need-to-show-costs-for-last-6-months-on-complicated-sub-queries","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-need-to-show-costs-for-last-6-months-on-complicated-sub-queries\/","title":{"rendered":"[Solved] Need to show costs for last 6 months on complicated sub queries"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-44803185\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"44803185\" data-parentid=\"44759660\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Right I have an answer which works, but it is not the best solution by any means. I really wanted to answer my question with one query, but the only solution I have come up with is to use php and loop the mysql. Yes I know this is not ideal, but I needed to find a solution quickly and even though it isn&#8217;t the best way, it works. I will carry on and see if I can work out a way of doing this with JUST mysql, but at the moment this will have to do.<\/p>\n<p>Basically my query is doing one month at a time. So I have to increment the month in php and re-run the query for all 6 months.<\/p>\n<p>Looking for a better solution now.<\/p>\n<pre><code>$plArray = array();\nfor ($i = 0; $i &lt;= 5; $i++):\n    $month  = date(\"m\", strtotime( date( 'Y-m-01' ).\" -$i months\"));\n    $query=\"SELECT IFNULL(`totalSales`,0)-IFNULL(`totalPurchase`,0)-(IFNULL(`totalNetpay`,0)+IFNULL(`totalP32`,0)+IFNULL(`totalPension`,0)) as `totalPL`\";\n    $query.=\"\n    FROM (SELECT SUM((`Unit_Cost`*`ExchangeRate`)*`Quantity`) AS `totalSales` FROM `salesinvoice_products` AS `prod`\n    LEFT JOIN `salesinvoice` AS `inv` on `prod`.`SalesInvoice_id`=`inv`.`SalesInvoice_id`\n    WHERE MONTH(`InvoiceDate`)=?\n    ) as `t1`,\n\n    (SELECT SUM((`InvoiceValue`*`ExchangeRate`)-`VATValue`) as `totalPurchase` FROM `purchaseinvoice`\n    WHERE MONTH(`InvoiceDate`)=?\n    ) as `t2`,\n\n    (SELECT SUM(`NetAmountPaid`) as `totalNetpay` FROM `payroll_netpay`\n    WHERE MONTH(`Date`)=?\n    ) as `t3`,\n\n    (SELECT SUM(`totalAmountDue`) as `totalPension` FROM `payroll_pensionrecords`\n    WHERE MONTH(`datePaid`)=?\n    ) as `t4`,\n\n    (SELECT SUM(`totalAmountDue`) as `totalP32` FROM `payroll_p32records`\n    WHERE MONTH(`datePaid`)=?\n    ) as `t5`\";\n    $stmt = $this-&gt;logon-&gt;db-&gt;prepare($query);\n    $stmt-&gt;bind_param('iiiii',$month,$month,$month,$month,$month);\n    $stmt-&gt;execute();\n    $result = $this-&gt;functions-&gt;get_result($stmt);\n    $plArray[] = array(\n    'date' =&gt; date(\"Y-m\", strtotime( date( 'Y-m-01' ).\" -$i months\")),\n    'total' =&gt; $result[0]['totalPL']\n    );\nendfor; \n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Need to show costs for last 6 months on complicated sub queries <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Right I have an answer which works, but it is not the best solution by any means. I really wanted to answer my question with one query, but the only solution I have come up with is to use php and loop the mysql. Yes I know this is not ideal, but I needed &#8230; <a title=\"[Solved] Need to show costs for last 6 months on complicated sub queries\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-need-to-show-costs-for-last-6-months-on-complicated-sub-queries\/\" aria-label=\"More on [Solved] Need to show costs for last 6 months on complicated sub queries\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[340,953],"class_list":["post-8674","post","type-post","status-publish","format-standard","hentry","category-solved","tag-mysql","tag-select"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Need to show costs for last 6 months on complicated sub queries - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-need-to-show-costs-for-last-6-months-on-complicated-sub-queries\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Need to show costs for last 6 months on complicated sub queries - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Right I have an answer which works, but it is not the best solution by any means. 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