{"id":8485,"date":"2022-09-13T21:49:45","date_gmt":"2022-09-13T16:19:45","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-start-the-forloop-counter-from-a-different-index\/"},"modified":"2022-09-13T21:49:45","modified_gmt":"2022-09-13T16:19:45","slug":"solved-how-to-start-the-forloop-counter-from-a-different-index","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-start-the-forloop-counter-from-a-different-index\/","title":{"rendered":"[Solved] how to start the forloop.counter from a different index"},"content":{"rendered":"

[ad_1]
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I’m not comfortable with Django, so I show a couple of option in plain Python, given the collections:<\/p>\n

something1 = [1,2,3,4]\nsomething2 = [1,2,3,4,5,6,7,8,9,10]\n<\/code><\/pre>\n
You can access objects by index (not the same as database index):<\/p>\n
i = 1\nfor e1 in something1:\n  print(e1)\n  i += 1\n\nfor i2 in range(i,len(something2)):\n  print(something2[i2])\n<\/code><\/pre>\n
Or slice the last collection:<\/p>\n
for e1 in something1:\n  print(e1)\n\nfor e2 in something2[len(something1):-1]:\n  print(e2)\n<\/code><\/pre>\n
Of course, the last collection has to be the longest.<\/p>\n<\/p><\/div>\n
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            <\/span> <\/p><\/div>\n<\/div>\n
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solved how to start the forloop.counter from a different index <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] I’m not comfortable with Django, so I show a couple of option in plain Python, given the collections: something1 = [1,2,3,4] something2 = [1,2,3,4,5,6,7,8,9,10] You can access objects by index (not the same as database index): i = 1 for e1 in something1: print(e1) i += 1 for i2 in range(i,len(something2)): print(something2[i2]) Or slice … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[2414,2412,593,2413,499],"class_list":["post-8485","post","type-post","status-publish","format-standard","hentry","category-solved","tag-django-1-11","tag-django-templates","tag-for-loop","tag-jinja2","tag-python-2-7"],"yoast_head":"\n[Solved] how to start the forloop.counter from a different index - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-start-the-forloop-counter-from-a-different-index\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] how to start the forloop.counter from a different index - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] I’m not comfortable with Django, so I show a couple of option in plain Python, given the collections: something1 = [1,2,3,4] something2 = [1,2,3,4,5,6,7,8,9,10] You can access objects by index (not the same as database index): i = 1 for e1 in something1: print(e1) i += 1 for i2 in range(i,len(something2)): print(something2[i2]) Or slice ... 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