{"id":8384,"date":"2022-09-13T08:18:43","date_gmt":"2022-09-13T02:48:43","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-plot-with-confidence-intervals-from-1d-data\/"},"modified":"2022-09-13T08:18:43","modified_gmt":"2022-09-13T02:48:43","slug":"solved-plot-with-confidence-intervals-from-1d-data","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-plot-with-confidence-intervals-from-1d-data\/","title":{"rendered":"[Solved] Plot with confidence intervals from 1D data?"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-14182176\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"14182176\" data-parentid=\"14182128\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>As the first google match stated, you can try doing as:<\/p>\n<pre><code>n&lt;-50\nx&lt;-sample(40:70,n,rep=T)\ny&lt;-.7*x+rnorm(n,sd=5)\nplot(x,y,xlim=c(20,90),ylim=c(0,80))\nmylm&lt;-lm(y~x)\nabline(mylm,col=\"red\")\nnewx&lt;-seq(20,90)\nprd&lt;-predict(mylm,newdata=data.frame(x=newx),interval = c(\"confidence\"), \nlevel = 0.90,type=\"response\")\nlines(newx,prd[,2],col=\"red\",lty=2)\nlines(newx,prd[,3],col=\"red\",lty=2)\n<\/code><\/pre>\n<p>Of course it is one of possibilities<br \/>\nAnother example would be:<\/p>\n<pre><code>x &lt;- rnorm(15)\ny &lt;- x + rnorm(15)\nnew &lt;- data.frame(x = seq(-3, 3, 0.5))\n\npred.w.clim &lt;- predict(lm(y ~ x), new, interval=\"confidence\")\n\n\n# Just create a blank plot region with axes first. We'll add to this\nplot(range(new$x), range(pred.w.clim), type = \"n\", ann = FALSE)\n\n\n# For convenience\nCI.U &lt;- pred.w.clim[, \"upr\"]\nCI.L &lt;- pred.w.clim[, \"lwr\"]\n\n# Create a 'loop' around the x values. Add values to 'close' the loop\nX.Vec &lt;- c(new$x, tail(new$x, 1), rev(new$x), new$x[1])\n\n# Same for y values\nY.Vec &lt;- c(CI.L, tail(CI.U, 1), rev(CI.U), CI.L[1])\n\n# Use polygon() to create the enclosed shading area\n# We are 'tracing' around the perimeter as created above\npolygon(X.Vec, Y.Vec, col = \"grey\", border = NA)\n\n\n# Use matlines() to plot the fitted line and CI's\n# Add after the polygon above so the lines are visible\nmatlines(new$x, pred.w.clim, lty = c(1, 2, 2), type = \"l\", col =  \nc(\"black\", \"red\", \"red\")) \n<\/code><\/pre>\n<p><a rel=\"nofollow noopener\" target=\"_blank\" href=\"http:\/\/stat.ethz.ch\/pipermail\/r-help\/2007-November\/146285.html\">Example 1<\/a><\/p>\n<p><a rel=\"nofollow noopener\" target=\"_blank\" href=\"http:\/\/r.789695.n4.nabble.com\/plotting-confidence-intervals-td897422.html\">Example 2<\/a><\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">6<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Plot with confidence intervals from 1D data? <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] As the first google match stated, you can try doing as: n&lt;-50 x&lt;-sample(40:70,n,rep=T) y&lt;-.7*x+rnorm(n,sd=5) plot(x,y,xlim=c(20,90),ylim=c(0,80)) mylm&lt;-lm(y~x) abline(mylm,col=&#8221;red&#8221;) newx&lt;-seq(20,90) prd&lt;-predict(mylm,newdata=data.frame(x=newx),interval = c(&#8220;confidence&#8221;), level = 0.90,type=&#8221;response&#8221;) lines(newx,prd[,2],col=&#8221;red&#8221;,lty=2) lines(newx,prd[,3],col=&#8221;red&#8221;,lty=2) Of course it is one of possibilities Another example would be: x &lt;- rnorm(15) y &lt;- x + rnorm(15) new &lt;- data.frame(x = seq(-3, 3, 0.5)) pred.w.clim &lt;- &#8230; <a title=\"[Solved] Plot with confidence intervals from 1D data?\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-plot-with-confidence-intervals-from-1d-data\/\" aria-label=\"More on [Solved] Plot with confidence intervals from 1D data?\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[321,1030],"class_list":["post-8384","post","type-post","status-publish","format-standard","hentry","category-solved","tag-r","tag-statistics"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Plot with confidence intervals from 1D data? - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-plot-with-confidence-intervals-from-1d-data\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Plot with confidence intervals from 1D data? - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] As the first google match stated, you can try doing as: n&lt;-50 x&lt;-sample(40:70,n,rep=T) y&lt;-.7*x+rnorm(n,sd=5) plot(x,y,xlim=c(20,90),ylim=c(0,80)) mylm&lt;-lm(y~x) abline(mylm,col=&quot;red&quot;) newx&lt;-seq(20,90) prd&lt;-predict(mylm,newdata=data.frame(x=newx),interval = c(&quot;confidence&quot;), level = 0.90,type=&quot;response&quot;) lines(newx,prd[,2],col=&quot;red&quot;,lty=2) lines(newx,prd[,3],col=&quot;red&quot;,lty=2) Of course it is one of possibilities Another example would be: x &lt;- rnorm(15) y &lt;- x + rnorm(15) new &lt;- data.frame(x = seq(-3, 3, 0.5)) pred.w.clim &lt;- ... 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