{"id":7958,"date":"2022-09-11T03:47:34","date_gmt":"2022-09-10T22:17:34","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-difference-between-and\/"},"modified":"2022-09-11T03:47:34","modified_gmt":"2022-09-10T22:17:34","slug":"solved-difference-between-and","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-difference-between-and\/","title":{"rendered":"[Solved] Difference between , and ;?"},"content":{"rendered":"

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You have not written a copy constructor or a copy assignment operator. The Rule of 3<\/a> tells us that anytime a destructor has been written, the copy assignment operator and copy constructor should be as well. You haven’t written either so let’s look at what happens:<\/p>\n

    \n
  1. l3 = l1<\/code> in this line the implicitly defined copy assignment operator<\/a> is called which will be defined like this:<\/li>\n<\/ol>\n
    Libro& Libro::operator=(const Libro& rhs) {\n    this.tiulo_ = rhs.titulo_;\n    this.paginas_ = rhs.paginas_;\n}\n<\/code><\/pre>\n
      \n
    1. this.tiulo_ = rhs.titulo_<\/code> This means that both the l1<\/code> and l3<\/code> objects point to the “Fundamentos de C++” string that was dynamically allocated by l1<\/code>‘s constructor<\/li>\n
    2. l3.~Libro()<\/code> is called implicitly as l3<\/code> leaves scope<\/a> which will call delete [] titulo_<\/code> destroying the “Fundamentos de C++” dynamically allocated member of l3<\/code> which is also l1<\/code>‘s titulo_<\/code> member<\/strong>.<\/li>\n
    3. l1.~Libro()<\/code> is called implicitly as well, which will call delete [] titulo_<\/code> however this time that member was deleted by l3<\/code> leaving scope, for a deleted pointer<\/a>:<\/li>\n<\/ol>\n
      \n
      Passing it to a deallocation function (double-delete) is undefined behavior<\/p>\n<\/blockquote>\n
      So your issue is not the ,<\/code> versus the ;<\/code> but the double-delete that results from not following The Rule of 3.<\/p>\n
      \n
      If I may though, rather than suggesting you create a copy constructor and copy assignment operator, I’d suggest you do away with Libro<\/code> and use string<\/code><\/a> in a `pair your code would be as simple as this:<\/p>\n
      pair<string, int> l1 = make_pair(\"Fundamentos de C++\"s, 474), l2 = make_pair(\"Por Fin: C ISO\"s, 224), l3;\n<\/code><\/pre>\n
      This will of course require you to explicitly output each member, for example:<\/p>\n
      cout << l1.first << \" tiene \" << l1.second << \" paginas\\n\" << l2.first << \" tiene \" << l2.second << \" paginas\\n\" << l3.first << \" tiene \" << l3.second << \" paginas\\n\";\n<\/code><\/pre>\n
      Live Example<\/kbd><\/a><\/p>\n<\/p><\/div>\n
      <\/div>\n<\/div>\n
                  2<\/span> <\/p><\/div>\n<\/div>\n
      [ad_2]<\/p>\n
      solved Difference between , and ;? <\/p>\n","protected":false},"excerpt":{"rendered":"
      [ad_1] You have not written a copy constructor or a copy assignment operator. The Rule of 3 tells us that anytime a destructor has been written, the copy assignment operator and copy constructor should be as well. You haven’t written either so let’s look at what happens: l3 = l1 in this line the implicitly … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,513],"class_list":["post-7958","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-c11"],"yoast_head":"\n[Solved] Difference between , and ;? - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-difference-between-and\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Difference between , and ;? - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You have not written a copy constructor or a copy assignment operator. 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