{"id":7801,"date":"2022-09-10T10:35:15","date_gmt":"2022-09-10T05:05:15","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-convert-list-to-xml-document-in-c\/"},"modified":"2022-09-10T10:35:15","modified_gmt":"2022-09-10T05:05:15","slug":"solved-how-to-convert-list-to-xml-document-in-c","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-convert-list-to-xml-document-in-c\/","title":{"rendered":"[Solved] How to convert List to xml document in c#"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-18734284\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"18734284\" data-parentid=\"18734230\" data-score=\"3\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>You may use XElement or XDocument and LINQ. Providing a sample of what the XML should look like we could provide more info.<\/p>\n<p>For instance:<\/p>\n<pre><code>BugWSResponseList1.Add(\"&lt;Bug&gt;&lt;family&gt;TEST22&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;\");\n\nBugWSResponseList1.Add(\"&lt;Bug&gt;&lt;family&gt;ESG&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;\");\n\nXElement xe = new XElement\n              (\n                  \"Bugs\",\n                  BugWSResponseList1\n                  .Select \n                  (\n                      x=&gt;\n                      XElement.Parse(x)\n                  )\n              );\n<\/code><\/pre>\n<p>So after i have loaded the list with the two pieces of xml you have provided i do the following:<\/p>\n<p>I create a new XElement that will hold the root of the XML. I name that root as <code>Bugs<\/code>. Then as children of that root i put the contents of your List after parsing them into XElement objects.<\/p>\n<p>The above code will result to :<\/p>\n<pre><code>&lt;Bugs&gt;\n  &lt;Bug&gt;\n    &lt;family&gt;TEST22&lt;\/family&gt;\n    &lt;product&gt;Dr.Watson&lt;\/product&gt;\n    &lt;version&gt;Xpress API&lt;\/version&gt;\n    &lt;productarea&gt;1&lt;\/productarea&gt;\n    &lt;subarea&gt;&lt;\/subarea&gt;\n    &lt;qe&gt;sdawar&lt;\/qe&gt;\n    &lt;duplicateId&gt;&lt;\/duplicateId&gt;\n  &lt;\/Bug&gt;\n  &lt;Bug&gt;\n    &lt;family&gt;ESG&lt;\/family&gt;\n    &lt;product&gt;Dr.Watson&lt;\/product&gt;\n    &lt;version&gt;Xpress API&lt;\/version&gt;\n    &lt;productarea&gt;1&lt;\/productarea&gt;\n    &lt;subarea&gt;&lt;\/subarea&gt;\n    &lt;qe&gt;sdawar&lt;\/qe&gt;\n    &lt;duplicateId&gt;&lt;\/duplicateId&gt;\n  &lt;\/Bug&gt;\n&lt;\/Bugs&gt;\n<\/code><\/pre>\n<p>What you were missing was the root element. XmlDocument needs to have a root element defined. <\/p>\n<p>In your case you could get away with it in you code by just adding  in the start of your joined string and  in the end, like the following, but i think my solution is more robust.<\/p>\n<pre><code>XmlDocument xd = new XmlDocument();\nstring s = \"&lt;Bugs&gt;\" + string.Join(\",\", BugWSResponseList2) + \"&lt;\/Bugs&gt;\";                    \nxd.LoadXml(s);\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">4<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to convert List<string> to xml document in c# <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] You may use XElement or XDocument and LINQ. Providing a sample of what the XML should look like we could provide more info. For instance: BugWSResponseList1.Add(&#8220;&lt;Bug&gt;&lt;family&gt;TEST22&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;&#8221;); BugWSResponseList1.Add(&#8220;&lt;Bug&gt;&lt;family&gt;ESG&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;&#8221;); XElement xe = new XElement ( &#8220;Bugs&#8221;, BugWSResponseList1 .Select ( x=&gt; XElement.Parse(x) ) ); So after i have loaded the list with the two pieces &#8230; <a title=\"[Solved] How to convert List to xml document in c#\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-convert-list-to-xml-document-in-c\/\" aria-label=\"More on [Solved] How to convert List to xml document in c#\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,2185,577],"class_list":["post-7801","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-tstringlist","tag-xml"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to convert List to xml document in c# - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-convert-list-to-xml-document-in-c\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to convert List to xml document in c# - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You may use XElement or XDocument and LINQ. Providing a sample of what the XML should look like we could provide more info. For instance: BugWSResponseList1.Add(&quot;&lt;Bug&gt;&lt;family&gt;TEST22&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;&quot;); BugWSResponseList1.Add(&quot;&lt;Bug&gt;&lt;family&gt;ESG&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;&quot;); XElement xe = new XElement ( &quot;Bugs&quot;, BugWSResponseList1 .Select ( x=&gt; XElement.Parse(x) ) ); So after i have loaded the list with the two pieces ... 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Providing a sample of what the XML should look like we could provide more info. For instance: BugWSResponseList1.Add(\"&lt;Bug&gt;&lt;family&gt;TEST22&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;\"); BugWSResponseList1.Add(\"&lt;Bug&gt;&lt;family&gt;ESG&lt;\/family&gt;&lt;product&gt;Dr.Watson&lt;\/product&gt;&lt;version&gt;Xpress API&lt;\/version&gt;&lt;productarea&gt;1&lt;\/productarea&gt;&lt;subarea&gt;&lt;\/subarea&gt;&lt;qe&gt;sdawar&lt;\/qe&gt;&lt;duplicateId&gt;&lt;\/duplicateId&gt;&lt;\/Bug&gt;\"); XElement xe = new XElement ( \"Bugs\", BugWSResponseList1 .Select ( x=&gt; XElement.Parse(x) ) ); So after i have loaded the list with the two pieces ... 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