{"id":7202,"date":"2022-09-07T11:42:42","date_gmt":"2022-09-07T06:12:42","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-vba-dictionary-for-uniqueness-count\/"},"modified":"2022-09-07T11:42:42","modified_gmt":"2022-09-07T06:12:42","slug":"solved-vba-dictionary-for-uniqueness-count","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-vba-dictionary-for-uniqueness-count\/","title":{"rendered":"[Solved] VBA Dictionary for uniqueness count"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-39261535\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"39261535\" data-parentid=\"39261503\" data-score=\"2\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>This should give the basic idea &#8211; Use the item you want to count as the key, and the count itself as the value.  If it is already in the Dictionary, increment it.  If not, add it:<\/p>\n<pre><code>Const TEST_DATA = \"Apple,Orange,Banana,Banana,Orange,Pear\"\n\nSub Example()\n    Dim counter As New Scripting.Dictionary\n    Dim testData() As String\n\n    testData = Split(TEST_DATA, \",\")\n    Dim i As Long\n    For i = LBound(testData) To UBound(testData)\n        If Not counter.Exists(testData(i)) Then\n            counter.Add testData(i), 1\n        Else\n            counter.Item(testData(i)) = counter.Item(testData(i)) + 1\n        End If\n    Next \n\n    Dim key As Variant\n    For Each key In counter.Keys\n        Debug.Print key, counter(key)\n    Next      \nEnd Sub\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">4<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved VBA Dictionary for uniqueness count <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] This should give the basic idea &#8211; Use the item you want to count as the key, and the count itself as the value. If it is already in the Dictionary, increment it. If not, add it: Const TEST_DATA = &#8220;Apple,Orange,Banana,Banana,Orange,Pear&#8221; Sub Example() Dim counter As New Scripting.Dictionary Dim testData() As String testData = &#8230; <a title=\"[Solved] VBA Dictionary for uniqueness count\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-vba-dictionary-for-uniqueness-count\/\" aria-label=\"More on [Solved] VBA Dictionary for uniqueness count\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[834,400,401],"class_list":["post-7202","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dictionary","tag-excel","tag-vba"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] VBA Dictionary for uniqueness count - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-vba-dictionary-for-uniqueness-count\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] VBA Dictionary for uniqueness count - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] This should give the basic idea &#8211; Use the item you want to count as the key, and the count itself as the value. If it is already in the Dictionary, increment it. If not, add it: Const TEST_DATA = &quot;Apple,Orange,Banana,Banana,Orange,Pear&quot; Sub Example() Dim counter As New Scripting.Dictionary Dim testData() As String testData = ... 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