{"id":6624,"date":"2022-09-04T08:29:41","date_gmt":"2022-09-04T02:59:41","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-break-down-long-multi-day-periods-of-time-into-several-single-day-periods\/"},"modified":"2022-09-04T08:29:41","modified_gmt":"2022-09-04T02:59:41","slug":"solved-break-down-long-multi-day-periods-of-time-into-several-single-day-periods","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-break-down-long-multi-day-periods-of-time-into-several-single-day-periods\/","title":{"rendered":"[Solved] Break down long multi day periods of time into several single day periods"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-57599796\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"57599796\" data-parentid=\"57599638\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>The method I have used here is a Tally Table to create extra rows. I <code>JOIN<\/code> onto the tally table where the number of hours \/ 24 (integer maths is useful) is greater than the tally number, and then can use that to calculate the hours. <\/p>\n<pre><code>WITH YourTable AS(\n    SELECT *\n    FROM (VALUES(1,CONVERT(date,'2018\/01\/24',111),4 ),\n                (2,CONVERT(date,'2018\/03\/21',111),40),\n                (3,CONVERT(date,'2018\/08\/16',111),33),\n                (4,CONVERT(date,'2018\/12\/01',111),8 ),\n                (5,CONVERT(date,'2018\/12\/17',111),56 ),\n                (6,CONVERT(date,'2018\/12\/17',111),24 ))V(VacationID,VacationDate,VacationDuration_Hr)),\n--Solution\nN AS(\n    SELECT N\n    FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL))N(N)),\nTally AS(\n    SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1 AS I\n    FROM N N1, N N2) -- 25 days, add more for more days\nSELECT YT.VacationID,\n       DATEADD(DAY, T.I, YT.VacationDate) AS VacationDate,\n       CASE WHEN VacationDuration_Hr - (T.I * 24) &gt; 24 THEN 24 ELSE YT.VacationDuration_Hr - (T.I * 24) END AS VacationDuration_Hr\nFROM YourTable YT\n     JOIN Tally T ON (YT.VacationDuration_Hr -1) \/ 24 &gt;= T.I\nORDER BY YT.VacationID,\n         T.I;\n<\/code><\/pre>\n<p>You <em>could<\/em> also use an rCTE here instead, however, I tend to avoid those for things like this; especially when I have no context of what the upper limit to the value of <code>VacationDuration_Hr<\/code> could be. if it is large it <em>could<\/em> have some nasty performance implications and a Tally will significantly out perform the RBAR nature of an rCTE.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">5<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Break down long multi day periods of time into several single day periods <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] The method I have used here is a Tally Table to create extra rows. I JOIN onto the tally table where the number of hours \/ 24 (integer maths is useful) is greater than the tally number, and then can use that to calculate the hours. WITH YourTable AS( SELECT * FROM (VALUES(1,CONVERT(date,&#8217;2018\/01\/24&#8242;,111),4 ), &#8230; <a title=\"[Solved] Break down long multi day periods of time into several single day periods\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-break-down-long-multi-day-periods-of-time-into-several-single-day-periods\/\" aria-label=\"More on [Solved] Break down long multi day periods of time into several single day periods\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[341,500,1009],"class_list":["post-6624","post","type-post","status-publish","format-standard","hentry","category-solved","tag-sql","tag-sql-server","tag-tsql"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Break down long multi day periods of time into several single day periods - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-break-down-long-multi-day-periods-of-time-into-several-single-day-periods\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Break down long multi day periods of time into several single day periods - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] The method I have used here is a Tally Table to create extra rows. I JOIN onto the tally table where the number of hours \/ 24 (integer maths is useful) is greater than the tally number, and then can use that to calculate the hours. WITH YourTable AS( SELECT * FROM (VALUES(1,CONVERT(date,&#039;2018\/01\/24&#039;,111),4 ), ... 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I JOIN onto the tally table where the number of hours \/ 24 (integer maths is useful) is greater than the tally number, and then can use that to calculate the hours. WITH YourTable AS( SELECT * FROM (VALUES(1,CONVERT(date,'2018\/01\/24',111),4 ), ... 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