{"id":6128,"date":"2022-09-01T13:58:50","date_gmt":"2022-09-01T08:28:50","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-use-a-formatted-string-to-separate-groups-of-digits\/"},"modified":"2022-09-01T13:58:50","modified_gmt":"2022-09-01T08:28:50","slug":"solved-use-a-formatted-string-to-separate-groups-of-digits","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-use-a-formatted-string-to-separate-groups-of-digits\/","title":{"rendered":"[Solved] Use a formatted string to separate groups of digits"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

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This is one way to achieve what you are looking to do:<\/p>\n

number = \"12345678910\"\nprint(\n    'number id {0}.{1}.{2}-{3}'.format(\n        *[number[i:i+3] for i in range(0,len(number), 3)]\n    )\n)\n#number id 123.456.789-10.\n<\/code><\/pre>\n
There are a few problems with your code. First the first number in the \"{0...}\"<\/code> refers to the positional argument in the format()<\/code> function. In your case, you were using all 0<\/code> which refers to the first argument only. This is why the same substring was being repeated over and over. (Notice how I changed it to {0}.{1}...{3}<\/code>.)<\/p>\n
I am passing *[number[i:i+3] for i in range(0,len(number), 3)]<\/code> to the format function, which just breaks your string into chunks of 3.<\/p>\n
print([number[i:i+3] for i in range(0,len(number), 3)])\n#['123', '456', '789', '10']\n<\/code><\/pre>\n
The *<\/code> operator does argument unpacking, which passes the elements of the list in order to format()<\/code>.<\/p>\n
\n
Update<\/strong>:<\/p>\n
As @user2357112 mentioned in the comments, you don’t actually need anything inside the braces in this case. Just use {}<\/code> to represent placeholders. <\/p>\n
print(\n    'number id {}.{}.{}-{}'.format(\n        *[number[i:i+3] for i in range(0,len(number), 3)]\n    )\n)\n<\/code><\/pre>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            0<\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved Use a formatted string to separate groups of digits <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] This is one way to achieve what you are looking to do: number = “12345678910” print( ‘number id {0}.{1}.{2}-{3}’.format( *[number[i:i+3] for i in range(0,len(number), 3)] ) ) #number id 123.456.789-10. There are a few problems with your code. First the first number in the “{0…}” refers to the positional argument in the format() function. … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[349,1273],"class_list":["post-6128","post","type-post","status-publish","format-standard","hentry","category-solved","tag-python","tag-string-formatting"],"yoast_head":"\n[Solved] Use a formatted string to separate groups of digits - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-use-a-formatted-string-to-separate-groups-of-digits\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Use a formatted string to separate groups of digits - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] This is one way to achieve what you are looking to do: number = "12345678910" print( 'number id {0}.{1}.{2}-{3}'.format( *[number[i:i+3] for i in range(0,len(number), 3)] ) ) #number id 123.456.789-10. There are a few problems with your code. First the first number in the "{0...}" refers to the positional argument in the format() function. ... 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There are a few problems with your code. First the first number in the \"{0...}\" refers to the positional argument in the format() function. ... 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