{"id":5785,"date":"2022-08-30T13:27:02","date_gmt":"2022-08-30T07:57:02","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-group-data-in-one-column-based-on-a-string-value-in-another-column-using-dplyr\/"},"modified":"2022-08-30T13:27:02","modified_gmt":"2022-08-30T07:57:02","slug":"solved-group-data-in-one-column-based-on-a-string-value-in-another-column-using-dplyr","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-group-data-in-one-column-based-on-a-string-value-in-another-column-using-dplyr\/","title":{"rendered":"[Solved] Group data in one column based on a string value in another column using dplyr"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-58153302\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"58153302\" data-parentid=\"58153206\" data-score=\"3\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>You can filter the data based on the column, then do the count for task : <\/p>\n<pre class=\"lang-r prettyprint-override\"><code>df &lt;- data.frame(\n  student = c(\n    rep(\"A\", 4), rep(\"B\", 4), rep(\"C\", 4), rep(\"D\", 4)\n  ), \n  task = rep(\n    c(\"Home\", \"Class\", \"Assign\", \"Poster\"), 4\n  ), \n  res = sample(\n    c(\"Completed\", \"Pending\", \"Not performed\"), \n    16, TRUE\n  )\n) \n\nlibrary(dplyr)\n#&gt; \n#&gt; Attaching package: 'dplyr'\n#&gt; The following objects are masked from 'package:stats':\n#&gt; \n#&gt;     filter, lag\n#&gt; The following objects are masked from 'package:base':\n#&gt; \n#&gt;     intersect, setdiff, setequal, union\ndf %&gt;% \n  filter(res == \"Completed\") %&gt;%\n  count(task)\n#&gt; # A tibble: 4 x 2\n#&gt;   task       n\n#&gt;   &lt;fct&gt;  &lt;int&gt;\n#&gt; 1 Assign     1\n#&gt; 2 Class      1\n#&gt; 3 Home       1\n#&gt; 4 Poster     3\n<\/code><\/pre>\n<p><sup>Created on 2019-09-29 by the <a rel=\"nofollow noopener\" target=\"_blank\" href=\"https:\/\/reprex.tidyverse.org\">reprex package<\/a> (v0.3.0)<\/sup><\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Group data in one column based on a string value in another column using dplyr <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] You can filter the data based on the column, then do the count for task : df &lt;- data.frame( student = c( rep(&#8220;A&#8221;, 4), rep(&#8220;B&#8221;, 4), rep(&#8220;C&#8221;, 4), rep(&#8220;D&#8221;, 4) ), task = rep( c(&#8220;Home&#8221;, &#8220;Class&#8221;, &#8220;Assign&#8221;, &#8220;Poster&#8221;), 4 ), res = sample( c(&#8220;Completed&#8221;, &#8220;Pending&#8221;, &#8220;Not performed&#8221;), 16, TRUE ) ) library(dplyr) #&gt; #&gt; &#8230; <a title=\"[Solved] Group data in one column based on a string value in another column using dplyr\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-group-data-in-one-column-based-on-a-string-value-in-another-column-using-dplyr\/\" aria-label=\"More on [Solved] Group data in one column based on a string value in another column using dplyr\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1256,321],"class_list":["post-5785","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dplyr","tag-r"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Group data in one column based on a string value in another column using dplyr - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-group-data-in-one-column-based-on-a-string-value-in-another-column-using-dplyr\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Group data in one column based on a string value in another column using dplyr - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You can filter the data based on the column, then do the count for task : df &lt;- data.frame( student = c( rep(&quot;A&quot;, 4), rep(&quot;B&quot;, 4), rep(&quot;C&quot;, 4), rep(&quot;D&quot;, 4) ), task = rep( c(&quot;Home&quot;, &quot;Class&quot;, &quot;Assign&quot;, &quot;Poster&quot;), 4 ), res = sample( c(&quot;Completed&quot;, &quot;Pending&quot;, &quot;Not performed&quot;), 16, TRUE ) ) library(dplyr) #&gt; #&gt; ... 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