{"id":5592,"date":"2022-08-29T15:58:37","date_gmt":"2022-08-29T10:28:37","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-xml-nodes-with-sql\/"},"modified":"2022-08-29T15:58:37","modified_gmt":"2022-08-29T10:28:37","slug":"solved-xml-nodes-with-sql","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-xml-nodes-with-sql\/","title":{"rendered":"[Solved] XML nodes with SQL"},"content":{"rendered":"

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Please try the following solution. What we are doing here is called shredding, i.e. converting XML into rectangular\/relational format.<\/p>\n

I am shooting from the hip because DDL and sample data population<\/strong> were not provided.<\/p>\n

The provided XML is not well-formed due to missing root element, but SQL Server allows to handle XML fragments.<\/p>\n

We are using XQuery and its .nodes()<\/code> and .value()<\/code> methods.<\/p>\n

SQL, Method #1<\/strong><\/p>\n

-- DDL and sample data population, start\nDECLARE @xml XML =\nN'<DW>\n    <KS>\n        <KeyInfo Name=\"IlluSetting\">\n            <KeyTypeValue>Text<\/KeyTypeValue>\n            <ValueString>yDipol90<\/ValueString>\n        <\/KeyInfo>\n        <KeyInfo Name=\"IlluSetting2\">\n            <KeyTypeValue>Text<\/KeyTypeValue>\n            <ValueString>yDipol<\/ValueString>\n        <\/KeyInfo>\n    <\/KS>\n    <MDESC>Tx [mrad]<\/MDESC>\n    <MNUMBER>0.12102<\/MNUMBER>\n<\/DW>\n<DW>\n    <KS>\n        <KeyInfo Name=\"IlluSetting3\">\n            <KeyTypeValue>Text<\/KeyTypeValue>\n            <ValueString>yDipol80<\/ValueString>\n        <\/KeyInfo>\n    <\/KS>\n    <MDESC>Ty [mrad]<\/MDESC>\n    <MNUMBER>0.12102<\/MNUMBER>\n<\/DW>';\n-- DDL and sample data population, end\n\nSELECT c.value('KeyInfo[1]\/@Name', 'VARCHAR(30)') AS name1\n    , c.value('(KeyInfo[1]\/ValueString\/text())[1]', 'VARCHAR(30)') AS ValueString1\n    , COALESCE(c.value('KeyInfo[2]\/@Name', 'VARCHAR(30)'), '') AS name2\n    , COALESCE(c.value('(KeyInfo[2]\/ValueString\/text())[1]', 'VARCHAR(30)'), '') AS ValueString2\nFROM @xml.nodes('\/DW\/KS') AS t(c);\n<\/code><\/pre>\n
Output<\/strong><\/p>\n
+--------------+--------------+--------------+--------------+\n|    name1     | ValueString1 |    name2     | ValueString2 |\n+--------------+--------------+--------------+--------------+\n| IlluSetting  | yDipol90     | IlluSetting2 | yDipol       |\n| IlluSetting3 | yDipol80     |              |              |\n+--------------+--------------+--------------+--------------+\n<\/code><\/pre>\n
SQL, Method #2<\/strong><\/p>\n
DECLARE @CrLf CHAR(2) = CHAR(13) + CHAR(10)\n   , @tokenCounter INT\n   , @i INT = 1;\n\n-- Calculate max number of tokens in the <KS>\nSET @tokenCounter = (SELECT MAX(c.value('count(KeyInfo)', 'INT'))\nFROM @xml.nodes('\/DW\/KS') AS t(c));\n\nDECLARE @SQL NVARCHAR(MAX) = 'SELECT ';\n\nWHILE @i <= @tokenCounter BEGIN\n    SET @SQL += IIF(@i>1,', ','') + 'COALESCE(c.value(''KeyInfo[' + CAST(@i AS VARCHAR(3)) + ']\/@Name'', ''VARCHAR(30)''), '''') AS NAME' + CAST(@i AS VARCHAR(3)) + @CrLf\n    SET @SQL += ', COALESCE(c.value(''(KeyInfo[' + CAST(@i AS VARCHAR(3)) + ']\/ValueString\/text())[1]'', ''VARCHAR(30)''), '''') AS ValueString' + CAST(@i AS VARCHAR(3)) + @CrLf\n\n    SET @i += 1\nEND\n\nSET @SQL += 'FROM @xml.nodes(''\/DW\/KS'') AS t(c);';\n\n-- just to see it\nPRINT @sql;\n\n-- we are ready at this point\nEXEC sp_executesql @stmt = @SQL, @params = N'@xml xml', @xml = @xml;\n<\/code><\/pre>\n<\/p><\/div>\n
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            3<\/span> <\/p><\/div>\n<\/div>\n
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solved XML nodes with SQL <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Please try the following solution. What we are doing here is called shredding, i.e. converting XML into rectangular\/relational format. I am shooting from the hip because DDL and sample data population were not provided. The provided XML is not well-formed due to missing root element, but SQL Server allows to handle XML fragments. We … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1444,341,500,577,1443],"class_list":["post-5592","post","type-post","status-publish","format-standard","hentry","category-solved","tag-shred","tag-sql","tag-sql-server","tag-xml","tag-xquery"],"yoast_head":"\n[Solved] XML nodes with SQL - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-xml-nodes-with-sql\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] XML nodes with SQL - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Please try the following solution. What we are doing here is called shredding, i.e. converting XML into rectangular\/relational format. I am shooting from the hip because DDL and sample data population were not provided. The provided XML is not well-formed due to missing root element, but SQL Server allows to handle XML fragments. We ... 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