{"id":5435,"date":"2022-08-28T16:25:00","date_gmt":"2022-08-28T10:55:00","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-get-the-n-if-i-know-the-result-of-123-nnn1-2-duplicate\/"},"modified":"2022-08-28T16:25:00","modified_gmt":"2022-08-28T10:55:00","slug":"solved-how-to-get-the-n-if-i-know-the-result-of-123-nnn1-2-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-get-the-n-if-i-know-the-result-of-123-nnn1-2-duplicate\/","title":{"rendered":"[Solved] How to get the n if I know the result of 1+2+3+..+n=n*(n+1)\/2? [duplicate]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-41921440\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"41921440\" data-parentid=\"41921370\" data-score=\"2\" data-position-on-page=\"2\" data-highest-scored=\"0\" data-question-has-accepted-highest-score=\"0\" itemprop=\"suggestedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Only by <strong>addition<\/strong> and <strong>subtraction<\/strong>&#8230;<br \/>\nSimply add numbers from 1 and check whether the sum is the given number.<\/p>\n<p>In pseudocode.<br \/>\nGiven 5050. <\/p>\n<pre><code>number := 5050\nnext, sum := 0\nwhile sum &lt;= number\n  next := next + 1\n  sum := sum + next\nreturn next\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">3<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to get the n if I know the result of 1+2+3+..+n=n*(n+1)\/2? [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Only by addition and subtraction&#8230; Simply add numbers from 1 and check whether the sum is the given number. In pseudocode. Given 5050. number := 5050 next, sum := 0 while sum &lt;= number next := next + 1 sum := sum + next return next 3 [ad_2] solved How to get the n &#8230; <a title=\"[Solved] How to get the n if I know the result of 1+2+3+..+n=n*(n+1)\/2? [duplicate]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-get-the-n-if-i-know-the-result-of-123-nnn1-2-duplicate\/\" aria-label=\"More on [Solved] How to get the n if I know the result of 1+2+3+..+n=n*(n+1)\/2? [duplicate]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[457,324],"class_list":["post-5435","post","type-post","status-publish","format-standard","hentry","category-solved","tag-algorithm","tag-c"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to get the n if I know the result of 1+2+3+..+n=n*(n+1)\/2? [duplicate] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-get-the-n-if-i-know-the-result-of-123-nnn1-2-duplicate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to get the n if I know the result of 1+2+3+..+n=n*(n+1)\/2? [duplicate] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Only by addition and subtraction&#8230; Simply add numbers from 1 and check whether the sum is the given number. In pseudocode. Given 5050. number := 5050 next, sum := 0 while sum &lt;= number next := next + 1 sum := sum + next return next 3 [ad_2] solved How to get the n ... 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