{"id":5374,"date":"2022-08-28T09:52:53","date_gmt":"2022-08-28T04:22:53","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-cannot-use-makeintchannel-value-of-type-intchannel-as-consumer-value-in-variable-declaration\/"},"modified":"2022-08-28T09:52:53","modified_gmt":"2022-08-28T04:22:53","slug":"solved-cannot-use-makeintchannel-value-of-type-intchannel-as-consumer-value-in-variable-declaration","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-cannot-use-makeintchannel-value-of-type-intchannel-as-consumer-value-in-variable-declaration\/","title":{"rendered":"[Solved] cannot use make(IntChannel) (value of type IntChannel) as Consumer value in variable declaration"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-68996854\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"68996854\" data-parentid=\"68995907\" data-score=\"3\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"js-endorsements\" data-for-answer=\"68996854\">\n<\/div>\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>First, you declared <code>Consumer<\/code> as a <code>chan<\/code> of <code>interface{ \/* methods *\/ }<\/code>, which most surely isn&#8217;t what you want \u2014 as a matter of fact, the error tells that you can&#8217;t assign <code>IntChannel<\/code> to it.<\/p>\n<p>Then, until generics are added to the language, you don&#8217;t have a way to preserve type safety.<\/p>\n<p>The closest solution to what you want to do might be adding an additional method to the interface that returns something that you can <code>range<\/code> over.<\/p>\n<pre><code>type Consumer interface {\n    OpenChannel()\n    CloseChannel()\n    Range() &lt;-chan interface{}\n}\n\ntype IntChannel chan int\n\nfunc (c IntChannel) OpenChannel() {\n}\n\nfunc (c IntChannel) CloseChannel() {\n}\n\nfunc (c IntChannel) Range() &lt;-chan interface{} {\n    ret := make(chan interface{})\n    go func() {\n        defer close(ret)\n        for v := range c {\n            ret &lt;- v\n        }\n    }()\n    return ret\n}\n\nfunc main() {\n    c := make(IntChannel)\n    var dataChannel Consumer = c\n    go func() {\n        c &lt;- 12\n        close(c)\n    }()\n    for data := range dataChannel.Range() {\n        fmt.Println(data)\n    }\n}\n<\/code><\/pre>\n<p>Go1 Playground: <a rel=\"nofollow noopener\" target=\"_blank\" href=\"https:\/\/play.golang.org\/p\/55BpISRVadE\">https:\/\/play.golang.org\/p\/55BpISRVadE<\/a><\/p>\n<hr>\n<p>With generics (Go 1.18, early 2022), instead you can just define a parametrized type with underlying type <code>chan<\/code>:<\/p>\n<pre><code>package main\n\nimport \"fmt\"\n\ntype GenericChan[T] chan T\n\nfunc main() {\n    c := make(GenericChan[int])\n    go func() {\n        c &lt;- 12\n        close(c)\n    }()\n    for data := range c {\n        fmt.Println(data)\n    }\n}\n<\/code><\/pre>\n<p>Go2 Playground: <a rel=\"nofollow noopener\" target=\"_blank\" href=\"https:\/\/go2goplay.golang.org\/p\/HQJ36ego97i\">https:\/\/go2goplay.golang.org\/p\/HQJ36ego97i<\/a><\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">2<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved cannot use make(IntChannel) (value of type IntChannel) as Consumer value in variable declaration <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] First, you declared Consumer as a chan of interface{ \/* methods *\/ }, which most surely isn&#8217;t what you want \u2014 as a matter of fact, the error tells that you can&#8217;t assign IntChannel to it. Then, until generics are added to the language, you don&#8217;t have a way to preserve type safety. The &#8230; <a title=\"[Solved] cannot use make(IntChannel) (value of type IntChannel) as Consumer value in variable declaration\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-cannot-use-makeintchannel-value-of-type-intchannel-as-consumer-value-in-variable-declaration\/\" aria-label=\"More on [Solved] cannot use make(IntChannel) (value of type IntChannel) as Consumer value in variable declaration\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1342,596],"class_list":["post-5374","post","type-post","status-publish","format-standard","hentry","category-solved","tag-channel","tag-go"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] cannot use make(IntChannel) (value of type IntChannel) as Consumer value in variable declaration - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-cannot-use-makeintchannel-value-of-type-intchannel-as-consumer-value-in-variable-declaration\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] cannot use make(IntChannel) (value of type IntChannel) as Consumer value in variable declaration - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] First, you declared Consumer as a chan of interface{ \/* methods *\/ }, which most surely isn&#8217;t what you want \u2014 as a matter of fact, the error tells that you can&#8217;t assign IntChannel to it. Then, until generics are added to the language, you don&#8217;t have a way to preserve type safety. The ... 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Then, until generics are added to the language, you don&#8217;t have a way to preserve type safety. The ... 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