{"id":4851,"date":"2022-08-24T20:03:19","date_gmt":"2022-08-24T14:33:19","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-replace-items-in-a-dict-of-nested-list-and-dicts\/"},"modified":"2022-08-24T20:03:19","modified_gmt":"2022-08-24T14:33:19","slug":"solved-replace-items-in-a-dict-of-nested-list-and-dicts","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-replace-items-in-a-dict-of-nested-list-and-dicts\/","title":{"rendered":"[Solved] Replace items in a dict of nested list and dicts"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-59336734\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"59336734\" data-parentid=\"59336397\" data-score=\"0\" data-position-on-page=\"2\" data-highest-scored=\"0\" data-question-has-accepted-highest-score=\"0\" itemprop=\"suggestedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>A recursive function that creates a new nested dictionary, replacing a key value with a different value<\/p>\n<pre><code>def replace_key(elem, old_key, new_key):\n    if isinstance(elem, dict):\n        # nested dictionary\n        new_dic = {}\n        for k, v in elem.items():\n            if isinstance(v,dict) or isinstance(v, list):\n                new_dic[replace_key(k, old_key, new_key)] = replace_key(v, old_key, new_key)\n            else:\n                new_dic[replace_key(k, old_key, new_key)] = v\n\n        return new_dic\n\n    elif isinstance(elem, list):\n        # nested list\n        return [replace_key(t, old_key, new_key) for t in elem]\n\n    else:\n        return elem\n\n\ndi = {\"a\": \"A\", \"b\": \"B\", \"c\": [2, 4, 6, {\"a\": \"A\", \"b\": \"B\"}], \"d\": {\"a\": [2, 4, 6], \"b\": [5, 2, 1]}}\n\nprint(replace_key(di, 'a', 'z'))\n<\/code><\/pre>\n<p><strong>Output<\/strong><\/p>\n<pre><code>{'z': 'A', 'c': [2, 4, 6, {'z': 'A', 'b': 'B'}], 'd': {'z': [2, 4, 6], 'b': [5, 2, 1]}, 'b': 'B'}\n<\/code><\/pre>\n<p>**Performance Comparison (using Jupyter Notebook) **<\/p>\n<p><em>Result: ComplicatedPhenomenon post has the fastest time by 10X over other two methods.<\/em><\/p>\n<p><strong>1. Reznik Post&#8211;JSON load substitution<\/strong><\/p>\n<pre><code>   %timeit json.loads(json.dumps(di).replace('a', 'z'))\n<\/code><\/pre>\n<p>23.6 \u00b5s \u00b1 2.05 \u00b5s per loop (mean \u00b1 std. dev. of 7 runs, 10000 loops each)<\/p>\n<p><strong>2. DarrylG&#8211;Recursive Function<\/strong><\/p>\n<pre><code>%timeit replace_key(di, 'a', 'z')\n<\/code><\/pre>\n<p>20.1 \u00b5s \u00b1 424 ns per loop (mean \u00b1 std. dev. of 7 runs, 100000 loops each)<\/p>\n<p><strong>3. ComplicatedPhenomenon Post&#8211;specialized to particular structure<\/strong><\/p>\n<pre><code>%%timeit\nd = {\"a\": \"A\", \"b\": \"B\", \"c\": [2, 4, 6, {\"a\": \"A\", \"b\": \"B\"}], \"d\": {\"a\": [2, 4, 6], \"b\": [5, 2, 1]}}\nd['z'] = d.pop('a')           \nd['d']['z'] = d['d'].pop('a')      \nd['c'][3]['z'] = d['c'][3].pop('a') \n<\/code><\/pre>\n<p>2.03 \u00b5s \u00b1 211 ns per loop (mean \u00b1 std. dev. of 7 runs, 100000 loops each)<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">3<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Replace items in a dict of nested list and dicts <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] A recursive function that creates a new nested dictionary, replacing a key value with a different value def replace_key(elem, old_key, new_key): if isinstance(elem, dict): # nested dictionary new_dic = {} for k, v in elem.items(): if isinstance(v,dict) or isinstance(v, list): new_dic[replace_key(k, old_key, new_key)] = replace_key(v, old_key, new_key) else: new_dic[replace_key(k, old_key, new_key)] = v return &#8230; <a title=\"[Solved] Replace items in a dict of nested list and dicts\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-replace-items-in-a-dict-of-nested-list-and-dicts\/\" aria-label=\"More on [Solved] Replace items in a dict of nested list and dicts\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[834,349],"class_list":["post-4851","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dictionary","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Replace items in a dict of nested list and dicts - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-replace-items-in-a-dict-of-nested-list-and-dicts\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Replace items in a dict of nested list and dicts - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] A recursive function that creates a new nested dictionary, replacing a key value with a different value def replace_key(elem, old_key, new_key): if isinstance(elem, dict): # nested dictionary new_dic = {} for k, v in elem.items(): if isinstance(v,dict) or isinstance(v, list): new_dic[replace_key(k, old_key, new_key)] = replace_key(v, old_key, new_key) else: new_dic[replace_key(k, old_key, new_key)] = v return ... 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