{"id":34569,"date":"2023-03-31T00:59:42","date_gmt":"2023-03-30T19:29:42","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-i-have-been-on-this-question-for-quaring-the-document-for-two-days-straight-and-it-is-not-working-dont-want-to-cheat-can-you-point-the-problem\/"},"modified":"2023-03-31T00:59:42","modified_gmt":"2023-03-30T19:29:42","slug":"solved-i-have-been-on-this-question-for-quaring-the-document-for-two-days-straight-and-it-is-not-working-dont-want-to-cheat-can-you-point-the-problem","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-i-have-been-on-this-question-for-quaring-the-document-for-two-days-straight-and-it-is-not-working-dont-want-to-cheat-can-you-point-the-problem\/","title":{"rendered":"[Solved] i have been on this question for quaring the document for two days straight, and it is not working. don’t want to cheat, can you point the problem"},"content":{"rendered":"

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  1. When processing regular characters (final else clause) you read additional input instead of operating over text<\/code>, i.e. instead of:<\/li>\n<\/ol>\n
                    scanf(\"%c\", &document[parano][sentno][wordno][charno]);\n                printf(\"%c\\n\", document[parano][sentno][wordno][charno]);\n                charno++;\n<\/code><\/pre>\n
    you want to do:<\/p>\n
                    document[parano][sentno][wordno][charno++] = text[i];\n<\/code><\/pre>\n
    By the time we hit text[i] == ' '<\/code> for the first time the value of ***document<\/code> is “3\\n1 2\\n2\\n” but you wanted it to be “Learning”.<\/p>\n
      \n
    1. \n
      (not fixed) When processing a word (`text[i] == ‘ ‘) you expand current word, yet, you hard-code 1000 when you allocate it initially so this doesn’t make sense.  Be consistent.<\/p>\n<\/li>\n
    2. \n
      parano<\/code>, sentno<\/code>, wordno<\/code>, charno<\/code> is indices but same suggest they are counts.  It’s not wrong just confusing and why you have to wordno + 2<\/code> when relloc’ing.<\/p>\n<\/li>\n
    3. \n
      Terminate words with `\\0′.<\/p>\n<\/li>\n
    4. \n
      When you process ‘ ‘ you add another word which you may or may not need which is fine.  But when process a ‘.’ you look ahead to the following letter is a \\n<\/code> or not.  Be consistent.  If you look ahead then you need to check that i + 1 < len<\/code>, and it’s fragile, say, there is a stray space before the \\n<\/code>.<\/p>\n<\/li>\n
    5. \n
      (not fixed) Memory leaks.  As the size of the sub-elements (paragraph, sentences and words) are private implementation details of get_document()<\/code> you will have refactor the code to make those available.  I suggest:<\/p>\n<\/li>\n<\/ol>\n
      struct document {\n   char ****document;\n   size_t paragraphs;\n   size_t sentences;\n   size_t words;\n}\n<\/code><\/pre>\n
        \n
      1. \n
        (not fixed) Deduplicate.  Similar to the print functions, create a allocation function per type.<\/p>\n<\/li>\n
      2. \n
        (not fixed, really) get_input_text()<\/code>.  You split the into paragraphs then concatenate everything again into a local variable then copy it into a dynamically allocated variable:<\/p>\n<\/li>\n<\/ol>\n
           char *str = malloc(BUFFER_LEN);\n   for(size_t i = 0, l = 0; l < lines && i + 1 < BUFFER_LEN; i += strlen(str + i)) {\n       int rv = fgets(str + i, BUFFER_LEN - i, stdin);\n       if(!rv) {\n          \/\/ handle error\n          break;\n       }\n   }\n   return s;\n<\/code><\/pre>\n
          \n
        1. (not fixed) Separate i\/o from processing.  This simplifies testing and it makes it easier to figure out what is going on.  In main(), you read a query type then 1 to 3 numbers.  <\/code>scanf()` tells you how many items where read so you simply do.  As you don’t use the kth_ functions for anything else just combine then with print_ funci<\/li>\n<\/ol>\n
              int n = scanf(\"%d %d %d %d\", &type, &p, &s, &w);\n    switch(type) {\n        case 1:\n            if(n != 2) {\n              \/\/ handle error\n            }\n            print_paragraph(document, p);\n            break;\n        ...\n    }\n<\/code><\/pre>\n
            \n
          1. \n
            (not fixed) Add error checks for the remainingmalloc()<\/code>, strdup()<\/code> etc.<\/p>\n<\/li>\n
          2. \n
            Don’t hard-code magic values (1000).  I introduced the constant WORD_LEN<\/code> but you also have MAX_CHARACTERS which is kinda the same thing.<\/p>\n<\/li>\n
          3. \n
            (not fixed) Consider using char *s = strpbrk(text + i, \" .\\n\")<\/code> to copy a word at a time.  It will simplify \\0<\/code> handling, and likely to be faster than walking the text<\/code> a byte at a time, i.e. i += s - text + i<\/code>, just handle the s == NULL<\/code> special case.<\/p>\n<\/li>\n<\/ol>\n
            valgrind is now happy other than leaks (see above):<\/p>\n
            #include <assert.h>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#define MAX_CHARACTERS 1005\n#define MAX_PARAGRAPHS 5\n#define WORD_LEN 1000\n\nchar *kth_word_in_mth_sentence_of_nth_paragraph(char ****document, int p, int s, int w) {\n    return document[p - 1][s - 1][w - 1];\n}\n\nchar **kth_sentence_in_mth_paragraph(char ****document, int p, int s) {\n    return document[p - 1][s - 1];\n}\n\nchar ***kth_paragraph(char ****document, int p) {\n    return document[p - 1];\n}\n\nchar ****get_document(char* text) {\n    char ****document = malloc(sizeof ***document);\n    *document = malloc(sizeof **document);\n    **document = malloc(sizeof *document);\n    ***document = malloc(WORD_LEN);\n\n    \/*  declare some numbers as iterators for the words, sentences,etc.*\/\n    int parano = 0;\n    int sentno = 0;\n    int wordno = 0;\n    int charno = 0;\n    \/*  now iterate over the text filling and expanding the document at the same time*\/\n    \/*----------------------------------------------------------------------------------------------------*\/\n    \/*  feading data in those spaces*\/\n    size_t len = strlen(text);\n    for (size_t i = 0; i < len; i++) {\n        switch(text[i]) {\n            case ' ': {\n                document[parano][sentno][wordno][charno] = '\\0';\n\n                wordno++;\n                char **words = realloc(\n                    document[parano][sentno],\n                    (wordno + 1) * sizeof *document[parano][sentno]\n                );\n                if(!words) {\n                    printf(\"realloc of words failed\\n\");\n                    exit(1);\n                }\n                document[parano][sentno] = words;\n                document[parano][sentno][wordno] = malloc(WORD_LEN);\n                charno = 0;\n                break;\n            }\n            case '.': {\n                document[parano][sentno][wordno][charno] = '\\0';\n\n                sentno++;\n                char ***sentences = realloc(\n                    document[parano],\n                    (sentno + 1) * sizeof *document[parano]\n                );\n                if(!sentences) {\n                    printf(\"realloc of sentences failed\\n\");\n                    exit(1);\n                }\n                document[parano] = sentences;\n                document[parano][sentno] = malloc(sizeof **document);\n                wordno = 0;\n                document[parano][sentno][wordno] = malloc(WORD_LEN);\n                charno = 0;\n                break;\n            }\n            case '\\n': {\n                document[parano][sentno][wordno][charno] = '\\0';\n\n                parano++;\n                char ****paragraphs = realloc(\n                    document,\n                    (parano + 1) * sizeof *document\n                );\n                if(!paragraphs) {\n                    printf(\"realloc of paragraphs failed\\n\");\n                    exit(1);\n                }\n                document = paragraphs;\n                document[parano] = malloc(sizeof ***document);\n                sentno = 0;\n                document[parano][sentno] = malloc(sizeof **document);\n                wordno = 0;\n                document[parano][sentno][wordno] = malloc(WORD_LEN);\n                charno = 0;\n                break;\n            }\n            default: \/\/ character\n                document[parano][sentno][wordno][charno++] = text[i];\n        }\n    }\n    return document;\n}\n\nchar *get_input_text() {\n    int paragraph_count;\n    scanf(\"%d\", &paragraph_count);\n    char p[MAX_PARAGRAPHS][MAX_CHARACTERS];\n    char doc[MAX_CHARACTERS];\n    memset(doc, 0, sizeof doc);\n    getchar();\n    for (int i = 0; i < paragraph_count; i++) {\n        scanf(\"%[^\\n]%*c\", p[i]);\n        strcat(doc, p[i]);\n        if (i != paragraph_count - 1)\n            strcat(doc, \"\\n\");\n    }\n    return strdup(doc);\n}\n\nvoid print_word(char *word) {\n    printf(\"%s\", word);\n}\n\nvoid print_sentence(char **sentence) {\n    int word_count;\n    scanf(\"%d\", &word_count);\n    for(int i = 0; i < word_count; i++){\n        print_word(sentence[i]);\n        if(i + 1 != word_count)\n            printf(\" \");\n    }\n}\n\nvoid print_paragraph(char ***paragraph) {\n    int sentence_count;\n    scanf(\"%d\", &sentence_count);\n    for (int i = 0; i < sentence_count; i++) {\n        print_sentence(paragraph[i]);\n        printf(\".\");\n    }\n}\n\nint main() {\n    char *text = get_input_text();\n    char ****document = get_document(text);\n    int q;\n    scanf(\"%d\", &q);\n    while (q--) {\n        int type;\n        scanf(\"%d\", &type);\n        switch(type) {\n            case 1: {\n                int p;\n                scanf(\"%d\", &p);\n                print_paragraph(kth_paragraph(document, p));\n                break;\n            }\n            case 2: {\n                int p, s;\n                scanf(\"%d %d\", &p, &s);\n                print_sentence(kth_sentence_in_mth_paragraph(document, p, s));\n                break;\n            }\n            case 3: {\n                int p, s, w;\n                scanf(\"%d %d %d\", &p, &s, &w);\n                print_word(kth_word_in_mth_sentence_of_nth_paragraph(document, p, s, w));\n                break;\n            }\n            default:\n                printf(\"error\\n\");\n        }\n        printf(\"\\n\");\n    }\n    free(text);\n}\n<\/code><\/pre>\n
            Output as expected:<\/p>\n
            Learning pointers is more fun.It is good to have pointers.\nLearning C is fun\nLearning\n<\/code><\/pre>\n
            Btw, a whole different way of solving this is problem is keep the original input (text<\/code>) then write functions to directly extract a paragraph, sentence or word from that string.  If you input is huge then create an index, say, (paragraph<\/code>, sentence<\/code>, word<\/code>) to &text[i]<\/code>.<\/p>\n<\/p><\/div>\n
            <\/div>\n<\/div>\n
                        1<\/span> <\/p><\/div>\n<\/div>\n
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            solved i have been on this question for quaring the document for two days straight, and it is not working. don’t want to cheat, can you point the problem <\/p>\n","protected":false},"excerpt":{"rendered":"
            [ad_1] When processing regular characters (final else clause) you read additional input instead of operating over text, i.e. instead of: scanf(“%c”, &document[parano][sentno][wordno][charno]); printf(“%c\\n”, document[parano][sentno][wordno][charno]); charno++; you want to do: document[parano][sentno][wordno][charno++] = text[i]; By the time we hit text[i] == ‘ ‘ for the first time the value of ***document is “3\\n1 2\\n2\\n” but you wanted … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,712,2162],"class_list":["post-34569","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-pointers","tag-realloc"],"yoast_head":"\n[Solved] i have been on this question for quaring the document for two days straight, and it is not working. don't want to cheat, can you point the problem - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-i-have-been-on-this-question-for-quaring-the-document-for-two-days-straight-and-it-is-not-working-dont-want-to-cheat-can-you-point-the-problem\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] i have been on this question for quaring the document for two days straight, and it is not working. don't want to cheat, can you point the problem - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] When processing regular characters (final else clause) you read additional input instead of operating over text, i.e. instead of: scanf("%c", &document[parano][sentno][wordno][charno]); printf("%cn", document[parano][sentno][wordno][charno]); charno++; you want to do: document[parano][sentno][wordno][charno++] = text[i]; By the time we hit text[i] == ' ' for the first time the value of ***document is “3n1 2n2n” but you wanted ... 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