{"id":34315,"date":"2023-03-04T10:22:26","date_gmt":"2023-03-04T04:52:26","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-find-duplicate-number-in-array-and-print-the-last-duplicate-number-only-closed\/"},"modified":"2023-03-04T10:22:26","modified_gmt":"2023-03-04T04:52:26","slug":"solved-find-duplicate-number-in-array-and-print-the-last-duplicate-number-only-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-find-duplicate-number-in-array-and-print-the-last-duplicate-number-only-closed\/","title":{"rendered":"[Solved] Find duplicate number in array and print the last duplicate number only [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-60602673\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"60602673\" data-parentid=\"60601413\" data-score=\"-1\" data-position-on-page=\"2\" data-highest-scored=\"0\" data-question-has-accepted-highest-score=\"0\" itemprop=\"suggestedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Simple way is iterate and compare it. like below, I hope it may solve your problem<\/p>\n<pre><code> int[] a = {1,2,2,3,4,3,5,5,7};\n String b = \"\";\n int count=0;\n for(int i = 0; i&lt;a.length;i++){\n     for(int j=0; j&lt;a.length;j++){\n         if(a[i]==a[j]){\n             count++;\n         }\n     }\n     if(count&gt;1){\n         count=0;\n         b = String.valueOf(a[i]);\n     }else{\n         count = 0;\n     }\n }\n  System.out.println(\"last duplicate value : \"\n                       + b);\n<\/code><\/pre>\n<p>Java 8 feature same solution<\/p>\n<pre><code>String output=\"N\/A\";\n              Integer[] a = {1,2,7,2,3,4,3,5,5,7};\n               List&lt;Integer&gt; list= Arrays.asList(a);\n\n              list= list.stream().map(m-&gt;m).sorted(Comparator.reverseOrder()).collect(Collectors.toList());\n              List&lt;Integer&gt; listSample=list;\n               Optional&lt;Integer&gt; data = list.stream().filter(m-&gt;listSample.stream().filter(c-&gt;c==m).count()&gt;1).findFirst();\n              if(data.isPresent()) {\n                  output=  data.get().toString();\n              }\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">1<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Find duplicate number in array and print the last duplicate number only [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Simple way is iterate and compare it. like below, I hope it may solve your problem int[] a = {1,2,2,3,4,3,5,5,7}; String b = &#8220;&#8221;; int count=0; for(int i = 0; i&lt;a.length;i++){ for(int j=0; j&lt;a.length;j++){ if(a[i]==a[j]){ count++; } } if(count&gt;1){ count=0; b = String.valueOf(a[i]); }else{ count = 0; } } System.out.println(&#8220;last duplicate value : &#8221; &#8230; <a title=\"[Solved] Find duplicate number in array and print the last duplicate number only [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-find-duplicate-number-in-array-and-print-the-last-duplicate-number-only-closed\/\" aria-label=\"More on [Solved] Find duplicate number in array and print the last duplicate number only [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[361,517,323,738],"class_list":["post-34315","post","type-post","status-publish","format-standard","hentry","category-solved","tag-arrays","tag-duplicates","tag-java","tag-numbers"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Find duplicate number in array and print the last duplicate number only [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-find-duplicate-number-in-array-and-print-the-last-duplicate-number-only-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Find duplicate number in array and print the last duplicate number only [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Simple way is iterate and compare it. like below, I hope it may solve your problem int[] a = {1,2,2,3,4,3,5,5,7}; String b = &quot;&quot;; int count=0; for(int i = 0; i&lt;a.length;i++){ for(int j=0; j&lt;a.length;j++){ if(a[i]==a[j]){ count++; } } if(count&gt;1){ count=0; b = String.valueOf(a[i]); }else{ count = 0; } } System.out.println(&quot;last duplicate value : &quot; ... 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