{"id":33910,"date":"2023-02-15T15:16:41","date_gmt":"2023-02-15T09:46:41","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-merge-multiple-list-of-dict-with-same-value-in-common-key-closed\/"},"modified":"2023-02-15T15:16:41","modified_gmt":"2023-02-15T09:46:41","slug":"solved-merge-multiple-list-of-dict-with-same-value-in-common-key-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-merge-multiple-list-of-dict-with-same-value-in-common-key-closed\/","title":{"rendered":"[Solved] Merge multiple list of dict with same value in common key [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-44281891\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"44281891\" data-parentid=\"44280815\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>If you want a more pythonic way:<\/p>\n<pre><code>from itertools import groupby\nfrom pprint import pprint\nfrom collections import ChainMap\n\na = [{'a':0,'b':23}, {'a':3,'b':77}, {'a':1,'b':99}]\nb = [{'a':1,'c':666}, {'a':4,'c':546}]\nc = [{'d':33,'a':3}, {'d':1111,'a':4}, {'d':76,'a':1}, {'d':775,'a':0}]\nd = [{'a':2,'e':12}, {'a':4,'e':76}]\n\ndict_list = a + b + c + d\n\n# You just need to specify the key you want to use in the lambda function\n# There's no need to declare the different key values previously\nres = map(lambda dict_tuple: dict(ChainMap(*dict_tuple[1])),\n          groupby(sorted(dict_list,\n                         key=lambda sub_dict: sub_dict[\"a\"]),\n                  key=lambda sub_dict: sub_dict[\"a\"]))\n\npprint(list(res))\n<\/code><\/pre>\n<p>Outputs:<\/p>\n<pre><code>[{'a': 0, 'b': 23, 'd': 775},\n {'a': 1, 'b': 99, 'c': 666, 'd': 76},\n {'a': 2, 'e': 12},\n {'a': 3, 'b': 77, 'd': 33},\n {'a': 4, 'c': 546, 'd': 1111, 'e': 76}]\n<\/code><\/pre>\n<p>Edit (Improvement):<\/p>\n<p>You can also use<\/p>\n<pre><code>from _operator import itemgetter\nkey=itemgetter(\"a\")\n<\/code><\/pre>\n<p>instead of<\/p>\n<pre><code>key=lambda sub_dict: sub_dict[\"a\"]\n<\/code><\/pre>\n<p>The version with itemgetter is much faster. Using the example you provided:<\/p>\n<pre><code>- Lambda: 0.037109375ms\n- Itemgetter: 0.009033203125ms\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">1<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Merge multiple list of dict with same value in common key [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] If you want a more pythonic way: from itertools import groupby from pprint import pprint from collections import ChainMap a = [{&#8216;a&#8217;:0,&#8217;b&#8217;:23}, {&#8216;a&#8217;:3,&#8217;b&#8217;:77}, {&#8216;a&#8217;:1,&#8217;b&#8217;:99}] b = [{&#8216;a&#8217;:1,&#8217;c&#8217;:666}, {&#8216;a&#8217;:4,&#8217;c&#8217;:546}] c = [{&#8216;d&#8217;:33,&#8217;a&#8217;:3}, {&#8216;d&#8217;:1111,&#8217;a&#8217;:4}, {&#8216;d&#8217;:76,&#8217;a&#8217;:1}, {&#8216;d&#8217;:775,&#8217;a&#8217;:0}] d = [{&#8216;a&#8217;:2,&#8217;e&#8217;:12}, {&#8216;a&#8217;:4,&#8217;e&#8217;:76}] dict_list = a + b + c + d # You just need to specify the &#8230; <a title=\"[Solved] Merge multiple list of dict with same value in common key [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-merge-multiple-list-of-dict-with-same-value-in-common-key-closed\/\" aria-label=\"More on [Solved] Merge multiple list of dict with same value in common key [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[834,349],"class_list":["post-33910","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dictionary","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Merge multiple list of dict with same value in common key [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-merge-multiple-list-of-dict-with-same-value-in-common-key-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Merge multiple list of dict with same value in common key [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] If you want a more pythonic way: from itertools import groupby from pprint import pprint from collections import ChainMap a = [{&#039;a&#039;:0,&#039;b&#039;:23}, {&#039;a&#039;:3,&#039;b&#039;:77}, {&#039;a&#039;:1,&#039;b&#039;:99}] b = [{&#039;a&#039;:1,&#039;c&#039;:666}, {&#039;a&#039;:4,&#039;c&#039;:546}] c = [{&#039;d&#039;:33,&#039;a&#039;:3}, {&#039;d&#039;:1111,&#039;a&#039;:4}, {&#039;d&#039;:76,&#039;a&#039;:1}, {&#039;d&#039;:775,&#039;a&#039;:0}] d = [{&#039;a&#039;:2,&#039;e&#039;:12}, {&#039;a&#039;:4,&#039;e&#039;:76}] dict_list = a + b + c + d # You just need to specify the ... 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