{"id":33234,"date":"2023-02-05T17:15:06","date_gmt":"2023-02-05T11:45:06","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-merging-arrays-of-dictionaries\/"},"modified":"2023-02-05T17:15:06","modified_gmt":"2023-02-05T11:45:06","slug":"solved-merging-arrays-of-dictionaries","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-merging-arrays-of-dictionaries\/","title":{"rendered":"[Solved] Merging arrays of dictionaries"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-22043899\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"22043899\" data-parentid=\"22043388\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>How about the following:<\/p>\n<pre><code>\/\/define data1 and Data2\nvar data1 = new[]{\n                   new {id = 1, name = \"Oneeee\", version = 2},\n                   new {id = 2, name = \"Two\", version = 1},\n                   new {id = 3, name = \"Three\", version = 2},\n                   new {id = 4, name = \"Four\", version = 1},\n                   new {id = 5, name =\"Five\", version = 1}\n                 };\n\nvar data2 = new[] {\n                   new {id = 1,  name = \"One\", version = 1},\n                   new {id = 2, name = \"Two\", version = 1},\n                   new {id = 3, name = \"Threeee\", version = 3},\n                   new {id = 6, name = \"Six\", version = 2}\n                 };\n\/\/create a dictionary to handle lookups     \nvar dict1 = data1.ToDictionary (k =&gt; k.id);\nvar dict2 = data2.ToDictionary (k =&gt; k.id);\n\n\/\/ now query the data\nvar q = from k in dict1.Keys.Union(dict2.Keys)\n        select\n                dict1.ContainsKey(k) ? \n                  (\n                    dict2.ContainsKey(k) ?\n                    (\n                      dict1[k].version &gt; dict2[k].version ? dict1[k] : dict2[k]\n                    ) :\n                    dict1[k]\n                  ) :\n                  dict2[k];\n\n\/\/ convert enumerable back to array\nvar result = q.ToArray();\n<\/code><\/pre>\n<p>Alternative solution that is database friendly if data1 and data2 are tables&#8230;.<\/p>\n<pre><code> var q  = (\n            from d1 in data1\n            join d2 in data2 on d1.id equals d2.id into data2j\n            from d2j in data2j.DefaultIfEmpty()\n            where d2j == null || d1.version &gt;= d2j.version\n            select d1\n          ).Union(\n            from d2 in data2\n            join d1 in data1 on d2.id equals d1.id into data1j\n            from d1j in data1j.DefaultIfEmpty()\n           where d1j == null || d2.version &gt; d1j.version\n           select d2\n          );\n\n  var result = q.ToArray();\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Merging arrays of dictionaries <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] How about the following: \/\/define data1 and Data2 var data1 = new[]{ new {id = 1, name = &#8220;Oneeee&#8221;, version = 2}, new {id = 2, name = &#8220;Two&#8221;, version = 1}, new {id = 3, name = &#8220;Three&#8221;, version = 2}, new {id = 4, name = &#8220;Four&#8221;, version = 1}, new {id &#8230; <a title=\"[Solved] Merging arrays of dictionaries\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-merging-arrays-of-dictionaries\/\" aria-label=\"More on [Solved] Merging arrays of dictionaries\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[356],"class_list":["post-33234","post","type-post","status-publish","format-standard","hentry","category-solved","tag-json"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Merging arrays of dictionaries - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-merging-arrays-of-dictionaries\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Merging arrays of dictionaries - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] How about the following: \/\/define data1 and Data2 var data1 = new[]{ new {id = 1, name = &quot;Oneeee&quot;, version = 2}, new {id = 2, name = &quot;Two&quot;, version = 1}, new {id = 3, name = &quot;Three&quot;, version = 2}, new {id = 4, name = &quot;Four&quot;, version = 1}, new {id ... 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