{"id":32969,"date":"2023-02-03T09:35:14","date_gmt":"2023-02-03T04:05:14","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-why-is-the-integer-j-returning-a-i\/"},"modified":"2023-02-03T09:35:14","modified_gmt":"2023-02-03T04:05:14","slug":"solved-why-is-the-integer-j-returning-a-i","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-why-is-the-integer-j-returning-a-i\/","title":{"rendered":"[Solved] Why is the integer `j` returning a `i`?"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-30651480\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"30651480\" data-parentid=\"30651351\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>The * operator declares s as a pointer. This means that it will contain the address of the variable assigned. Here the value of the pointer s is i i.e, the first element of the string &#8220;iLoveC&#8221;. When you use post increment s[j++] it is equivalent to s[0]=&#8217;i&#8217; but when you use s[++j] it is equivalent to s[1]=&#8217;L&#8217;<\/p>\n<p>See this link <a rel=\"nofollow noopener\" target=\"_blank\" href=\"http:\/\/www.programiz.com\/c-programming\/c-pointers-arrays\">http:\/\/www.programiz.com\/c-programming\/c-pointers-arrays<\/a><br \/>\nand start by readind some books.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">1<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Why is the integer `j` returning a `i`? <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] The * operator declares s as a pointer. This means that it will contain the address of the variable assigned. Here the value of the pointer s is i i.e, the first element of the string &#8220;iLoveC&#8221;. When you use post increment s[j++] it is equivalent to s[0]=&#8217;i&#8217; but when you use s[++j] it &#8230; <a title=\"[Solved] Why is the integer `j` returning a `i`?\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-why-is-the-integer-j-returning-a-i\/\" aria-label=\"More on [Solved] Why is the integer `j` returning a `i`?\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324],"class_list":["post-32969","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Why is the integer `j` returning a `i`? - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-why-is-the-integer-j-returning-a-i\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Why is the integer `j` returning a `i`? - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] The * operator declares s as a pointer. This means that it will contain the address of the variable assigned. Here the value of the pointer s is i i.e, the first element of the string &#8220;iLoveC&#8221;. When you use post increment s[j++] it is equivalent to s[0]=&#8217;i&#8217; but when you use s[++j] it ... 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This means that it will contain the address of the variable assigned. Here the value of the pointer s is i i.e, the first element of the string &#8220;iLoveC&#8221;. When you use post increment s[j++] it is equivalent to s[0]=&#8217;i&#8217; but when you use s[++j] it ... 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