{"id":32928,"date":"2023-02-03T02:55:43","date_gmt":"2023-02-02T21:25:43","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-c-list-all-files-in-current-directory-then-move-in-directory-above-list-files-and-so-on-until-root-directory-is-reached-closed\/"},"modified":"2023-02-03T02:55:43","modified_gmt":"2023-02-02T21:25:43","slug":"solved-c-list-all-files-in-current-directory-then-move-in-directory-above-list-files-and-so-on-until-root-directory-is-reached-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-c-list-all-files-in-current-directory-then-move-in-directory-above-list-files-and-so-on-until-root-directory-is-reached-closed\/","title":{"rendered":"[Solved] C – list all files in current directory then move in directory above, list files, and so on until root directory is reached [closed]"},"content":{"rendered":"

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Your cwd[1] != 0<\/code> or cwd[1] != '\\0'<\/code> is an okay way to do it. There’s no need to cast that to an int.<\/p>\n

You could also use strcmp(cwd, \"https:\/\/stackoverflow.com\/\")<\/code>, which makes it slightly more clear what you are doing. This will be zero at the root directory on a UNIX or Linux system.<\/p>\n

For a more portable solution, you can compare the current directory name with the previous directory name, something like this:<\/p>\n

char cwd[1024];\nchar parent[1024];\ngetcwd(cwd, sizeof(cwd));\n<\/code><\/pre>\n
and inside the loop:<\/p>\n
        chdir(\"..\");\n        getcwd(parent, sizeof(parent));\n        if (strcmp(cwd, parent) == 0)\n                break;\n        strcpy(cwd, parent);\n<\/code><\/pre>\n
On a POSIX system, you can check if the current directory is the root without using getcwd()<\/code>, using code like this:<\/p>\n
int cwd_is_root(void)\n{\n        struct stat cwd, parent;\n        if (stat(\".\", &cwd) < 0)\n                return -1;\n        if (stat(\"..\", &parent) < 0)\n                return -1;\n        return cwd.st_ino == parent.st_ino && cwd.st_dev == parent.st_dev;\n}\n<\/code><\/pre>\n
It is simpler and better just to use getcwd<\/code> as you did, unless you are writing your own libc!  getcwd<\/code> is a system call on Linux.<\/p>\n<\/p><\/div>\n
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            1<\/span> <\/p><\/div>\n<\/div>\n
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solved C – list all files in current directory then move in directory above, list files, and so on until root directory is reached [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Your cwd[1] != 0 or cwd[1] != ‘\\0′ is an okay way to do it. There’s no need to cast that to an int. You could also use strcmp(cwd, “https:\/\/stackoverflow.com\/”), which makes it slightly more clear what you are doing. This will be zero at the root directory on a UNIX or Linux system. … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,424],"class_list":["post-32928","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-linux"],"yoast_head":"\n[Solved] C - list all files in current directory then move in directory above, list files, and so on until root directory is reached [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-c-list-all-files-in-current-directory-then-move-in-directory-above-list-files-and-so-on-until-root-directory-is-reached-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] C - list all files in current directory then move in directory above, list files, and so on until root directory is reached [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Your cwd[1] != 0 or cwd[1] != '' is an okay way to do it. There’s no need to cast that to an int. You could also use strcmp(cwd, "https:\/\/stackoverflow.com\/"), which makes it slightly more clear what you are doing. This will be zero at the root directory on a UNIX or Linux system. ... 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