{"id":32208,"date":"2023-01-27T10:48:56","date_gmt":"2023-01-27T05:18:56","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-back-for-the-beginning-if-the-user-press-any-key-except-1-or-2-or-3-closed\/"},"modified":"2023-01-27T10:48:56","modified_gmt":"2023-01-27T05:18:56","slug":"solved-how-to-back-for-the-beginning-if-the-user-press-any-key-except-1-or-2-or-3-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-back-for-the-beginning-if-the-user-press-any-key-except-1-or-2-or-3-closed\/","title":{"rendered":"[Solved] HOW to back for the beginning if the user press any key except 1 or 2 or 3? [closed]"},"content":{"rendered":"

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Use do<\/code>–while<\/code> loop and set the condition to while(L != '1' && L != '2' && L != '3');<\/code>:<\/p>\n

do {\n    L = getch();\n    switch (L) {\n    case '1' :\n        system(\"cls\"); \n        printf(\"111111111111111\");\n        break;\n    case '2' :\n        system(\"cls\");\n        printf(\"222222222222222\");\n        break;\n    case '3' :\n        system(\"cls\");\n        printf(\"33333333\");\n        break;\n    default :\n        sleep(0);\n    }\n} while(L != '1' && L != '2' && L != '3');\n<\/code><\/pre>\n
The code above will prompt for data first then evaluate it and continue these until user enters '1'<\/code>, '2'<\/code> or '3'<\/code>.<\/p>\n
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As comments bellow mention the default<\/code> case with sleep(0)<\/code> has no use but it can be improved e.g. as follows:<\/p>\n
do {\n    L = getch();\n    switch (L) {\n    case '1' :\n        system(\"cls\"); \n        printf(\"111111111111111\");\n        break;\n    case '2' :\n        system(\"cls\");\n        printf(\"222222222222222\");\n        break;\n    case '3' :\n        system(\"cls\");\n        printf(\"33333333\");\n        break;\n    default :\n        L = 0;\n    }\n} while(!L);\n<\/code><\/pre>\n
In this example you don’t have to double check for permitted values (assuming that you don’t want to use the case when L == 0<\/code>).<\/p>\n
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As the title of your question is a bit misleading maybe I didn’t understand what do you like to achieve. If you just want to suspend going back to the beginning of your loop, you can add an extra getch()<\/code> after the switch<\/code> block:<\/p>\n
while (1) {\n    L = getch();\n\n    switch (L) {\n    case '1':\n        system(\"cls\"); \n        printf(\"111111111111111\");\n        break;\n    case '2':\n        system(\"cls\");\n        printf(\"222222222222222\");\n        break;\n    case '3':\n        system(\"cls\");\n        printf(\"33333333\");\n        break;\n    }\n\n    printf(\"Press Any Key to Continue...\");\n    getch();\n}\n<\/code><\/pre>\n
If this still doesn’t answer your question I recommend you to improve it.<\/p>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            6<\/span> <\/p><\/div>\n<\/div>\n
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solved HOW to back for the beginning if the user press any key except 1 or 2 or 3? [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Use do–while loop and set the condition to while(L != ‘1’ && L != ‘2’ && L != ‘3’);: do { L = getch(); switch (L) { case ‘1’ : system(“cls”); printf(“111111111111111”); break; case ‘2’ : system(“cls”); printf(“222222222222222”); break; case ‘3’ : system(“cls”); printf(“33333333”); break; default : sleep(0); } } while(L != ‘1’ && … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,391,2933],"class_list":["post-32208","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-loops","tag-user-input"],"yoast_head":"\n[Solved] HOW to back for the beginning if the user press any key except 1 or 2 or 3? [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-back-for-the-beginning-if-the-user-press-any-key-except-1-or-2-or-3-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] HOW to back for the beginning if the user press any key except 1 or 2 or 3? [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Use do–while loop and set the condition to while(L != '1' && L != '2' && L != '3');: do { L = getch(); switch (L) { case '1' : system("cls"); printf("111111111111111"); break; case '2' : system("cls"); printf("222222222222222"); break; case '3' : system("cls"); printf("33333333"); break; default : sleep(0); } } while(L != '1' && ... 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