{"id":31428,"date":"2023-01-21T10:19:08","date_gmt":"2023-01-21T04:49:08","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-python-sort-dictionary-by-value-equal-values\/"},"modified":"2023-01-21T10:19:08","modified_gmt":"2023-01-21T04:49:08","slug":"solved-python-sort-dictionary-by-value-equal-values","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-python-sort-dictionary-by-value-equal-values\/","title":{"rendered":"[Solved] Python: Sort dictionary by value (equal values)"},"content":{"rendered":"

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dictionaries are unordered (well pre 3.6 at least), instead sort the items<\/p>\n

d = {3: '__init__', 5: 'other', 7: 'hey  ', 11: 'hey'}\nprint(sorted(d.items(),key=lambda item:(item[0].strip(),item[1])))\n\n# output => [(3, '__init__'), (7, 'hey  '), (11, 'hey'), (5, 'other')]\n<\/code><\/pre>\n
if you really want it as a dict (for reasons i cant fathom) and you are using 3.6+ then you can just  create a new dict from your sorted items<\/p>\n
d2 = dict(sorted(d.items(),key=lambda item:item[1]))\n<\/code><\/pre>\n
*(note that in 3.6 that dicts maintain order is an implementation detail, not a guarantee, but 3.7+ its part of the language specification)<\/p>\n
you can do the same thing in earlier pythons using collections.OrderedDict<\/p>\n
from collections import OrderedDict\nd2 = OrderedDict(sorted(d.items(),key=lambda item:item[1]))\n<\/code><\/pre>\n
since you cant use builtin sorted here is a bubble sort for you … although I dont understand how having strangers on the internet write a sort function for you is any better than just using the python builtin sorted<\/p>\n
def my_bubble_sort(list_thing,key_fn):\n    # sort a list in place by a key fn\n    changed = True\n    while changed:\n        changed = False\n        for i in range(len(list_thing)-1):\n            if key_fn(list_thing[i]) > key_fn(list_thing[i+1]):\n               list_thing[i],list_thing[i+1] = list_thing[i+1],list_thing[i]\n               changed = True\n\nd = {3: '__init__', 5: 'other', 7: 'hey  ', 11: 'hey'}\nd_list = d.items()\nmy_bubble_sort(d_list,lambda item:(item[1].strip(),item[0]))\nprint(d_list)\n<\/code><\/pre>\n<\/p><\/div>\n
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            5<\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved Python: Sort dictionary by value (equal values) <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] dictionaries are unordered (well pre 3.6 at least), instead sort the items d = {3: ‘__init__’, 5: ‘other’, 7: ‘hey ‘, 11: ‘hey’} print(sorted(d.items(),key=lambda item:(item[0].strip(),item[1]))) # output => [(3, ‘__init__’), (7, ‘hey ‘), (11, ‘hey’), (5, ‘other’)] if you really want it as a dict (for reasons i cant fathom) and you are using … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[834,540,349,1862,561],"class_list":["post-31428","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dictionary","tag-list","tag-python","tag-python-3-6","tag-sorting"],"yoast_head":"\n[Solved] Python: Sort dictionary by value (equal values) - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-python-sort-dictionary-by-value-equal-values\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Python: Sort dictionary by value (equal values) - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] dictionaries are unordered (well pre 3.6 at least), instead sort the items d = {3: '__init__', 5: 'other', 7: 'hey ', 11: 'hey'} print(sorted(d.items(),key=lambda item:(item[0].strip(),item[1]))) # output => [(3, '__init__'), (7, 'hey '), (11, 'hey'), (5, 'other')] if you really want it as a dict (for reasons i cant fathom) and you are using ... 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