{"id":31304,"date":"2023-01-20T16:14:24","date_gmt":"2023-01-20T10:44:24","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-divide-without-divide-c-closed\/"},"modified":"2023-01-20T16:14:24","modified_gmt":"2023-01-20T10:44:24","slug":"solved-divide-without-divide-c-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-divide-without-divide-c-closed\/","title":{"rendered":"[Solved] Divide without divide c++ [closed]"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

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Compare X<\/em> \u2261 s1 * m2<\/code> with Y<\/em> \u2261 s2 * m1<\/code>. If X<\/em> > Y<\/em>, then s1 \/ m1<\/code> > s2 \/ m2<\/code>.<\/p>\n

No division is required to do the comparison.<\/p>\n

The caveat to this solution is that s1<\/code>, s2<\/code>, m1<\/code>, and m2<\/code> should all have the same sign, and m1<\/code> and m2<\/code> should be non-zero.<\/sup><\/sub><\/p>\n

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Let’s assume all the values are positive integers (hence, greater than 0). Consequently m1 * m2<\/code> is positive as well. Let z<\/em> be the number such that:<\/p>\n

\n

z<\/em> + (s1 \/ m1<\/code>) = s2 \/ m2<\/code><\/p>\n<\/blockquote>\n

By multiplying by m1 * m2<\/code> on both sides, we get:<\/p>\n

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z’<\/em> + (s1 * m2<\/code>) = s2 * m1<\/code> \u2235 z’<\/em> \u2261 z<\/em> \u00d7 (m1 * m2<\/code>)<\/p>\n<\/blockquote>\n

Since z<\/em> and z’<\/em> have the same sign, the relational order of s1 \/ m1<\/code> and s1 \/ m2<\/code> is the same as the relational order of s1 * m2<\/code> and s2 * m1<\/code>.<\/p>\n<\/p><\/div>\n

<\/div>\n<\/div>\n

2<\/span> <\/p><\/div>\n<\/div>\n

[ad_2]<\/p>\n

solved Divide without divide c++ [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"

[ad_1] Compare X \u2261 s1 * m2 with Y \u2261 s2 * m1. If X > Y, then s1 \/ m1 > s2 \/ m2. No division is required to do the comparison. The caveat to this solution is that s1, s2, m1, and m2 should all have the same sign, and m1 and m2 … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[457,324,357],"class_list":["post-31304","post","type-post","status-publish","format-standard","hentry","category-solved","tag-algorithm","tag-c","tag-math"],"yoast_head":"\n[Solved] Divide without divide c++ [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-divide-without-divide-c-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Divide without divide c++ [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Compare X \u2261 s1 * m2 with Y \u2261 s2 * m1. If X > Y, then s1 \/ m1 > s2 \/ m2. No division is required to do the comparison. The caveat to this solution is that s1, s2, m1, and m2 should all have the same sign, and m1 and m2 ... 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