{"id":31080,"date":"2023-01-19T08:56:46","date_gmt":"2023-01-19T03:26:46","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-get-all-3-digit-number-whose-sum-is-11-or-we-can-say-module-is-1-in-js-closed\/"},"modified":"2023-01-19T08:56:46","modified_gmt":"2023-01-19T03:26:46","slug":"solved-get-all-3-digit-number-whose-sum-is-11-or-we-can-say-module-is-1-in-js-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-get-all-3-digit-number-whose-sum-is-11-or-we-can-say-module-is-1-in-js-closed\/","title":{"rendered":"[Solved] get all 3 digit number whose sum is 11 or we can say module is 1 in JS [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-63863721\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"63863721\" data-parentid=\"63863329\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>I&#8217;m not sure what the second check is supposed to be (the modulus of something has to be <code>1<\/code>). If that is supposed to be that the modulus of all digits of the number has to be <code>1<\/code>, here is how you could do it:<\/p>\n<\/p>\n<div class=\"snippet\" data-lang=\"js\" data-hide=\"false\" data-console=\"true\" data-babel=\"false\">\n<div class=\"snippet-code\">\n<pre class=\"snippet-code-js lang-js prettyprint-override\"><code>var results = [];\nfor (let i = 1; i &lt; 10; i++) {\n  for (let j = 0; j &lt; 10; j++) {\n    for (let k = 0; k &lt; 10; k++) {\n      if (i + j + k === 11 &amp;&amp; i % j % k === 1) {\n        results.push(i.toString() + j.toString() + k.toString());\n      }\n    }\n  }\n}\n\nconsole.log(results);<\/code><\/pre>\n<\/div>\n<\/div>\n<p>OR:<\/p>\n<\/p>\n<div class=\"snippet\" data-lang=\"js\" data-hide=\"false\" data-console=\"true\" data-babel=\"false\">\n<div class=\"snippet-code\">\n<pre class=\"snippet-code-js lang-js prettyprint-override\"><code>var results = [];\nfor (let i = 100; i &lt; 1000; i++) {\n  const [one, two, three] = i.toString().split('').map(i =&gt; +i);\n  if (one + two + three === 11 &amp;&amp; one % two % three === 1) {\n    results.push(i.toString());\n  }\n}\n\nconsole.log(results);<\/code><\/pre>\n<\/div>\n<\/div>\n<p>Basically just go through all the possible combination and do the checks on each number.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved get all 3 digit number whose sum is 11 or we can say module is 1 in JS [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] I&#8217;m not sure what the second check is supposed to be (the modulus of something has to be 1). If that is supposed to be that the modulus of all digits of the number has to be 1, here is how you could do it: var results = []; for (let i = 1; &#8230; <a title=\"[Solved] get all 3 digit number whose sum is 11 or we can say module is 1 in JS [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-get-all-3-digit-number-whose-sum-is-11-or-we-can-say-module-is-1-in-js-closed\/\" aria-label=\"More on [Solved] get all 3 digit number whose sum is 11 or we can say module is 1 in JS [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[333,1948,902],"class_list":["post-31080","post","type-post","status-publish","format-standard","hentry","category-solved","tag-javascript","tag-javascript-objects","tag-node-js"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>[Solved] get all 3 digit number whose sum is 11 or we can say module is 1 in JS [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-get-all-3-digit-number-whose-sum-is-11-or-we-can-say-module-is-1-in-js-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] get all 3 digit number whose sum is 11 or we can say module is 1 in JS [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] I&#8217;m not sure what the second check is supposed to be (the modulus of something has to be 1). If that is supposed to be that the modulus of all digits of the number has to be 1, here is how you could do it: var results = []; for (let i = 1; ... 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