{"id":31033,"date":"2023-01-19T01:43:18","date_gmt":"2023-01-18T20:13:18","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-swift-for-in-loop-range-and-closedrange-errors\/"},"modified":"2023-01-19T01:43:18","modified_gmt":"2023-01-18T20:13:18","slug":"solved-swift-for-in-loop-range-and-closedrange-errors","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-swift-for-in-loop-range-and-closedrange-errors\/","title":{"rendered":"[Solved] Swift `for-in` loop Range and ClosedRange errors"},"content":{"rendered":"

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Swift ranges are written as 0...10<\/code>, not<\/strong><\/em> [0...10]<\/code>.<\/p>\n

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[0...10]<\/code> creates a single-item array. The first item in the array is a 0...10<\/code> range.<\/p>\n

Using for i in [0...10]<\/code> thus iterates over that single-item array, not<\/em> the range itself. The iterated value i<\/code> will be of type Range<\/code> or ClosedRange<\/code>.<\/p>\n

To iterate over each Int<\/code> in the range, as you expect to be doing, use the range 0...10<\/code> without<\/em> the brackets:<\/p>\n

for i in 0...10 {\n    \/\/ ...\n}\n\nfor i in 0..<10 {\n    \/\/ ...\n}\n<\/code><\/pre>\n
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https:\/\/docs.swift.org\/swift-book\/LanguageGuide\/ControlFlow.html<\/a><\/p>\n
You can also use for-in loops with numeric ranges. This example prints the first few entries in a five-times table:<\/p>\n
for index in 1...5 {\n    print(\"\\(index) times 5 is \\(index * 5)\")\n}\n<\/code><\/pre>\n
The sequence being iterated over is a range of numbers from 1 to 5, inclusive, as indicated by the use of the closed range operator (...)<\/code>.<\/p>\n<\/blockquote><\/div>\n
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            <\/span> <\/p><\/div>\n<\/div>\n
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solved Swift `for-in` loop Range and ClosedRange errors <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Swift ranges are written as 0…10, not [0…10]. [0…10] creates a single-item array. The first item in the array is a 0…10 range. Using for i in [0…10] thus iterates over that single-item array, not the range itself. The iterated value i will be of type Range or ClosedRange. To iterate over each Int … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[5784,593,1671,522],"class_list":["post-31033","post","type-post","status-publish","format-standard","hentry","category-solved","tag-for-in-loop","tag-for-loop","tag-range","tag-swift"],"yoast_head":"\n[Solved] Swift `for-in` loop Range and ClosedRange errors - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-swift-for-in-loop-range-and-closedrange-errors\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Swift `for-in` loop Range and ClosedRange errors - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Swift ranges are written as 0...10, not [0...10]. [0...10] creates a single-item array. The first item in the array is a 0...10 range. Using for i in [0...10] thus iterates over that single-item array, not the range itself. The iterated value i will be of type Range or ClosedRange. To iterate over each Int ... 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[0...10] creates a single-item array. The first item in the array is a 0...10 range. Using for i in [0...10] thus iterates over that single-item array, not the range itself. The iterated value i will be of type Range or ClosedRange. To iterate over each Int ... 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