{"id":30758,"date":"2023-01-17T05:06:07","date_gmt":"2023-01-16T23:36:07","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-convert-string-rule-to-an-expression-which-has-a-range-in-r-closed\/"},"modified":"2023-01-17T05:06:07","modified_gmt":"2023-01-16T23:36:07","slug":"solved-how-to-convert-string-rule-to-an-expression-which-has-a-range-in-r-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-convert-string-rule-to-an-expression-which-has-a-range-in-r-closed\/","title":{"rendered":"[Solved] How to convert string rule to an expression which has a range in R [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-63551221\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"63551221\" data-parentid=\"63551005\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>I&#8217;d do it in several steps:<\/p>\n<ol>\n<li>Split on logical operators into separate inequalities.<\/li>\n<li>Change double inequalities like -3&gt;x1&gt;=-1.45 into two inequalities.<\/li>\n<li>Change &#8220;=&#8221; to &#8220;==&#8221;, and put it all together.<\/li>\n<\/ol>\n<p>For example:<\/p>\n<pre><code>a1 &lt;- strsplit(a, \"&amp;\", fixed = TRUE)[[1]]\na1a &lt;- gsub(\" \", \"\", a1) # get rid of spaces\na2 &lt;- gsub(\"([-0-9.]+[&lt;&gt;=]+)([[:alpha:]]+[[:alnum:]]*)([&lt;&gt;=]+.+)\",\n           \"\\\\1\\\\2 &amp; \\\\2\\\\3\", a1a)\na3 &lt;- paste(gsub(\"[^&lt;&gt;]={1}\", \"==\", a2), collapse = \" &amp; \")\n<\/code><\/pre>\n<p>which gives <code>a3<\/code> equal to<\/p>\n<pre><code>[1] \"-3&gt;x1 &amp; x1&gt;=-1.45 &amp; -3&lt;=x2 &amp; x2&lt;3 &amp; x==7\"\n<\/code><\/pre>\n<p>This won&#8217;t work if you have other logical operations besides &amp;, or if your variables have non-alphanumeric characters like dots or underscores.  It will also fail on inequalities like <code>x1 &lt;= x2 &lt;= x3<\/code>.  I&#8217;ll leave you to handle those cases if they come up.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">3<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to convert string rule to an expression which has a range in R [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] I&#8217;d do it in several steps: Split on logical operators into separate inequalities. Change double inequalities like -3&gt;x1&gt;=-1.45 into two inequalities. Change &#8220;=&#8221; to &#8220;==&#8221;, and put it all together. For example: a1 &lt;- strsplit(a, &#8220;&amp;&#8221;, fixed = TRUE)[[1]] a1a &lt;- gsub(&#8221; &#8220;, &#8220;&#8221;, a1) # get rid of spaces a2 &lt;- gsub(&#8220;([-0-9.]+[&lt;&gt;=]+)([[:alpha:]]+[[:alnum:]]*)([&lt;&gt;=]+.+)&#8221;, &#8220;\\\\1\\\\2 &#8230; <a title=\"[Solved] How to convert string rule to an expression which has a range in R [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-convert-string-rule-to-an-expression-which-has-a-range-in-r-closed\/\" aria-label=\"More on [Solved] How to convert string rule to an expression which has a range in R [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1777,2499,1174,321,5763],"class_list":["post-30758","post","type-post","status-publish","format-standard","hentry","category-solved","tag-eval","tag-gsub","tag-nlp","tag-r","tag-string-substitution"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to convert string rule to an expression which has a range in R [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-convert-string-rule-to-an-expression-which-has-a-range-in-r-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to convert string rule to an expression which has a range in R [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] I&#8217;d do it in several steps: Split on logical operators into separate inequalities. Change double inequalities like -3&gt;x1&gt;=-1.45 into two inequalities. Change &#8220;=&#8221; to &#8220;==&#8221;, and put it all together. For example: a1 &lt;- strsplit(a, &quot;&amp;&quot;, fixed = TRUE)[[1]] a1a &lt;- gsub(&quot; &quot;, &quot;&quot;, a1) # get rid of spaces a2 &lt;- gsub(&quot;([-0-9.]+[&lt;&gt;=]+)([[:alpha:]]+[[:alnum:]]*)([&lt;&gt;=]+.+)&quot;, &quot;\\1\\2 ... 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Change double inequalities like -3&gt;x1&gt;=-1.45 into two inequalities. Change &#8220;=&#8221; to &#8220;==&#8221;, and put it all together. For example: a1 &lt;- strsplit(a, \"&amp;\", fixed = TRUE)[[1]] a1a &lt;- gsub(\" \", \"\", a1) # get rid of spaces a2 &lt;- gsub(\"([-0-9.]+[&lt;&gt;=]+)([[:alpha:]]+[[:alnum:]]*)([&lt;&gt;=]+.+)\", \"\\1\\2 ... 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