{"id":30198,"date":"2023-01-14T03:34:24","date_gmt":"2023-01-13T22:04:24","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-program-to-print-a-circle-of-given-diameter\/"},"modified":"2023-01-14T03:34:24","modified_gmt":"2023-01-13T22:04:24","slug":"solved-program-to-print-a-circle-of-given-diameter","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-program-to-print-a-circle-of-given-diameter\/","title":{"rendered":"[Solved] Program to print a circle of given diameter"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-27153421\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"27153421\" data-parentid=\"27152481\" data-score=\"2\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>You have to find the perimeter first, then divide it by the total number of rotations, then set that as the value of forward in your loop.<\/p>\n<p>E.g.<\/p>\n<pre><code>make \"d 100\nmake \"p 3.141592654*:d\nmake \"i :p\/36\nrepeat 36[fd :i rt 10]\n<\/code><\/pre>\n<p>you can have all of them in a single statement as <\/p>\n<pre><code>repeat 36[fd 3.141592654*:d\/36 rt 10]\n<\/code><\/pre>\n<p>where d is the accepted value of the diameter<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Program to print a circle of given diameter <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] You have to find the perimeter first, then divide it by the total number of rotations, then set that as the value of forward in your loop. E.g. make &#8220;d 100 make &#8220;p 3.141592654*:d make &#8220;i :p\/36 repeat 36[fd :i rt 10] you can have all of them in a single statement as repeat &#8230; <a title=\"[Solved] Program to print a circle of given diameter\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-program-to-print-a-circle-of-given-diameter\/\" aria-label=\"More on [Solved] Program to print a circle of given diameter\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[5708,1790,5707],"class_list":["post-30198","post","type-post","status-publish","format-standard","hentry","category-solved","tag-logo-lang","tag-turtle-graphics","tag-ucb-logo"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Program to print a circle of given diameter - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-program-to-print-a-circle-of-given-diameter\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Program to print a circle of given diameter - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You have to find the perimeter first, then divide it by the total number of rotations, then set that as the value of forward in your loop. E.g. make &quot;d 100 make &quot;p 3.141592654*:d make &quot;i :p\/36 repeat 36[fd :i rt 10] you can have all of them in a single statement as repeat ... 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