{"id":30064,"date":"2023-01-13T02:29:07","date_gmt":"2023-01-12T20:59:07","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-create-dictionary-within-a-dictionary-in-python\/"},"modified":"2023-01-13T02:29:07","modified_gmt":"2023-01-12T20:59:07","slug":"solved-how-to-create-dictionary-within-a-dictionary-in-python","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-create-dictionary-within-a-dictionary-in-python\/","title":{"rendered":"[Solved] how to create Dictionary within a dictionary in python"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-21726840\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"21726840\" data-parentid=\"21726518\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<pre><code>&gt;&gt;&gt; import json\n&gt;&gt;&gt; title, data = ('Marks_Subjects ', \"[['Time', 'maths', 'Science', 'english'], ['2013-08-31-16', 100, 50, 65]]\")\n&gt;&gt;&gt; title, sub_title = title.split('_')  # Split 'Mark' and 'Subjects'\n&gt;&gt;&gt; data = json.loads(data.replace(\"'\", '\"'))  # Deserialize the data list\n&gt;&gt;&gt; data = dict(zip(*data))  # make a dict of the two lists\n&gt;&gt;&gt; date = data.pop('Time')  # Extract the date\n&gt;&gt;&gt; # Create a dict using a comprehension.\n...\n&gt;&gt;&gt; {title: {subject: {date: {sub_title: mark}}\n...  for subject, mark in data.iteritems()}}\n{'Marks': {'maths': {'2013-08-31-16': {'Subjects ': 100}}, 'Science': {'2013-08-31-16': {'Subjects ': 50}}, 'english': {'2013-08-31-16': {'Subjects ': 65}}}}\n<\/code><\/pre>\n<p>I must say that this data structure doesn&#8217;t make sense.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">3<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved how to create Dictionary within a dictionary in python <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] &gt;&gt;&gt; import json &gt;&gt;&gt; title, data = (&#8216;Marks_Subjects &#8216;, &#8220;[[&#8216;Time&#8217;, &#8216;maths&#8217;, &#8216;Science&#8217;, &#8216;english&#8217;], [&#8216;2013-08-31-16&#8217;, 100, 50, 65]]&#8221;) &gt;&gt;&gt; title, sub_title = title.split(&#8216;_&#8217;) # Split &#8216;Mark&#8217; and &#8216;Subjects&#8217; &gt;&gt;&gt; data = json.loads(data.replace(&#8220;&#8216;&#8221;, &#8216;&#8221;&#8216;)) # Deserialize the data list &gt;&gt;&gt; data = dict(zip(*data)) # make a dict of the two lists &gt;&gt;&gt; date = data.pop(&#8216;Time&#8217;) # &#8230; <a title=\"[Solved] how to create Dictionary within a dictionary in python\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-create-dictionary-within-a-dictionary-in-python\/\" aria-label=\"More on [Solved] how to create Dictionary within a dictionary in python\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[349],"class_list":["post-30064","post","type-post","status-publish","format-standard","hentry","category-solved","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] how to create Dictionary within a dictionary in python - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-create-dictionary-within-a-dictionary-in-python\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] how to create Dictionary within a dictionary in python - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] &gt;&gt;&gt; import json &gt;&gt;&gt; title, data = (&#039;Marks_Subjects &#039;, &quot;[[&#039;Time&#039;, &#039;maths&#039;, &#039;Science&#039;, &#039;english&#039;], [&#039;2013-08-31-16&#039;, 100, 50, 65]]&quot;) &gt;&gt;&gt; title, sub_title = title.split(&#039;_&#039;) # Split &#039;Mark&#039; and &#039;Subjects&#039; &gt;&gt;&gt; data = json.loads(data.replace(&quot;&#039;&quot;, &#039;&quot;&#039;)) # Deserialize the data list &gt;&gt;&gt; data = dict(zip(*data)) # make a dict of the two lists &gt;&gt;&gt; date = data.pop(&#039;Time&#039;) # ... 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