{"id":28445,"date":"2022-12-31T00:39:31","date_gmt":"2022-12-30T19:09:31","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-r-subset-based-on-range-of-dates-closed\/"},"modified":"2022-12-31T00:39:31","modified_gmt":"2022-12-30T19:09:31","slug":"solved-r-subset-based-on-range-of-dates-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-r-subset-based-on-range-of-dates-closed\/","title":{"rendered":"[Solved] R subset based on range of dates [closed]"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

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<\/div>\n
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Are you asking something like the following?<\/p>\n

Let’s say your initial dataframe is df<\/em>, which is the following:<\/p>\n

df\n            A          B          C\n1  2016-02-16 2016-03-21 2016-01-01\n2  2016-07-07 2016-06-17 2016-01-31\n3  2016-05-19 2016-09-10 2016-03-01\n4  2016-01-14 2016-08-21 2016-04-01\n5  2016-09-02 2016-06-15 2016-05-01\n6  2016-05-09 2016-07-17 2016-05-31\n7  2016-06-13 2016-06-23 2016-07-01\n8  2016-09-17 2016-03-11 2016-07-31\n9  2016-03-09 2016-05-13 2016-08-30\n10 2016-01-20 2016-09-01 2016-09-30\n<\/code><\/pre>\n
Now if you do the following subset operation, we shall get the following dataframe subset:<\/p>\n
df.sub <- df[apply(df, 1, function(x) (x[3] < min(x[1], x[2])) | \n                                      (x[3] > max(x[1], x[2]))),]\ndf.sub\n            A          B          C\n1  2016-02-16 2016-03-21 2016-01-01\n2  2016-07-07 2016-06-17 2016-01-31\n3  2016-05-19 2016-09-10 2016-03-01\n5  2016-09-02 2016-06-15 2016-05-01\n7  2016-06-13 2016-06-23 2016-07-01\n9  2016-03-09 2016-05-13 2016-08-30\n10 2016-01-20 2016-09-01 2016-09-30\n<\/code><\/pre>\n
Hope it helps.<\/p>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            <\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved R subset based on range of dates [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Are you asking something like the following? Let’s say your initial dataframe is df, which is the following: df A B C 1 2016-02-16 2016-03-21 2016-01-01 2 2016-07-07 2016-06-17 2016-01-31 3 2016-05-19 2016-09-10 2016-03-01 4 2016-01-14 2016-08-21 2016-04-01 5 2016-09-02 2016-06-15 2016-05-01 6 2016-05-09 2016-07-17 2016-05-31 7 2016-06-13 2016-06-23 2016-07-01 8 2016-09-17 2016-03-11 2016-07-31 … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1544,321,2058],"class_list":["post-28445","post","type-post","status-publish","format-standard","hentry","category-solved","tag-conditional-statements","tag-r","tag-subset"],"yoast_head":"\n[Solved] R subset based on range of dates [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-r-subset-based-on-range-of-dates-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] R subset based on range of dates [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Are you asking something like the following? Let’s say your initial dataframe is df, which is the following: df A B C 1 2016-02-16 2016-03-21 2016-01-01 2 2016-07-07 2016-06-17 2016-01-31 3 2016-05-19 2016-09-10 2016-03-01 4 2016-01-14 2016-08-21 2016-04-01 5 2016-09-02 2016-06-15 2016-05-01 6 2016-05-09 2016-07-17 2016-05-31 7 2016-06-13 2016-06-23 2016-07-01 8 2016-09-17 2016-03-11 2016-07-31 ... 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