{"id":28334,"date":"2022-12-30T06:35:34","date_gmt":"2022-12-30T01:05:34","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-sql-differences-between-two-queries\/"},"modified":"2022-12-30T06:35:34","modified_gmt":"2022-12-30T01:05:34","slug":"solved-sql-differences-between-two-queries","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-sql-differences-between-two-queries\/","title":{"rendered":"[Solved] SQL &#8211; Differences between two queries"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-33832369\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"33832369\" data-parentid=\"33831920\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>The only difference is that the first query will return a row for each pair of rows in the table where <code>P1.att2 &gt; P2.att2 and P2.att1 = x<\/code>, while the second query will just return one row for each row in the table where <code>att2<\/code> is greater than in some row where <code>att1 = x<\/code>. For example, if the table contains:<\/p>\n<pre><code>att att1 att2\n1   x    10\n2   y    20\n3   x    15\n4   z    16\n5   a     5\n6   b    11\n<\/code><\/pre>\n<p>The first query will return<\/p>\n<pre><code>att\n2\n2\n3\n4\n4\n6\n<\/code><\/pre>\n<p><code>2<\/code> and <code>4<\/code> are returned twice because their <code>att2<\/code> are greater than <code>att2<\/code> in rows 1 and 3, but <code>3<\/code> and <code>5<\/code> are only greater than row 1. The second auery will just return:<\/p>\n<pre><code>att\n2\n3\n4\n6\n<\/code><\/pre>\n<p>If <code>att<\/code> is unique in each row, changing the first query to <code>SELECT DISTINCT P1.att<\/code> will get you the same result as in the first query. Or if there&#8217;s a primary key, you can use <code>GROUP BY primary_key_column<\/code>.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved SQL &#8211; Differences between two queries <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] The only difference is that the first query will return a row for each pair of rows in the table where P1.att2 &gt; P2.att2 and P2.att1 = x, while the second query will just return one row for each row in the table where att2 is greater than in some row where att1 = &#8230; <a title=\"[Solved] SQL &#8211; Differences between two queries\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-sql-differences-between-two-queries\/\" aria-label=\"More on [Solved] SQL &#8211; Differences between two queries\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[340,341],"class_list":["post-28334","post","type-post","status-publish","format-standard","hentry","category-solved","tag-mysql","tag-sql"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>[Solved] SQL - Differences between two queries - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-sql-differences-between-two-queries\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] SQL - Differences between two queries - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] The only difference is that the first query will return a row for each pair of rows in the table where P1.att2 &gt; P2.att2 and P2.att1 = x, while the second query will just return one row for each row in the table where att2 is greater than in some row where att1 = ... 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