{"id":28256,"date":"2022-12-29T16:55:27","date_gmt":"2022-12-29T11:25:27","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-breadth-first-search-exercise-ai\/"},"modified":"2022-12-29T16:55:27","modified_gmt":"2022-12-29T11:25:27","slug":"solved-breadth-first-search-exercise-ai","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-breadth-first-search-exercise-ai\/","title":{"rendered":"[Solved] Breadth-first Search Exercise &#8211; AI"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-26132124\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"26132124\" data-parentid=\"26131811\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Basically, you multiply the number of pieces with their individual potential mobility to get the theoretical branching factor for one side. That is, the number of possible moves at each search level. <\/p>\n<p>Then you raise that figure to the power of the search depth to get the number of total positions to evaluate. <\/p>\n<p>So if for the first search ply (half-move), the branching factor is N, then for a two-ply search the total number of positions is N*N, for three it&#8217;s N*N*N, and so on.<\/p>\n<p>I&#8217;ll leave the rest up to you \ud83d\ude42<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Breadth-first Search Exercise &#8211; AI <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Basically, you multiply the number of pieces with their individual potential mobility to get the theoretical branching factor for one side. That is, the number of possible moves at each search level. Then you raise that figure to the power of the search depth to get the number of total positions to evaluate. So &#8230; <a title=\"[Solved] Breadth-first Search Exercise &#8211; AI\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-breadth-first-search-exercise-ai\/\" aria-label=\"More on [Solved] Breadth-first Search Exercise &#8211; AI\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[586],"class_list":["post-28256","post","type-post","status-publish","format-standard","hentry","category-solved","tag-artificial-intelligence"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Breadth-first Search Exercise - AI - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-breadth-first-search-exercise-ai\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Breadth-first Search Exercise - AI - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Basically, you multiply the number of pieces with their individual potential mobility to get the theoretical branching factor for one side. That is, the number of possible moves at each search level. Then you raise that figure to the power of the search depth to get the number of total positions to evaluate. So ... 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