{"id":26187,"date":"2022-12-16T05:27:39","date_gmt":"2022-12-15T23:57:39","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-grouping-and-summarizing-closed\/"},"modified":"2022-12-16T05:27:39","modified_gmt":"2022-12-15T23:57:39","slug":"solved-grouping-and-summarizing-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-grouping-and-summarizing-closed\/","title":{"rendered":"[Solved] Grouping and summarizing [closed]"},"content":{"rendered":"

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Editing from previous wrong answer and borrowing from @akron for the use of rle<\/code>, you can do this: assuming that your data is in a data.frame named “df” and your “frame classes” are in a column named “frame_class”, as in the code below, this should work: <\/p>\n

df = data.frame(n_frame = seq(1:13), frame_type = \"frame_type\",\n                frame_class = c(\"I_frame\", \"P_frame\", \"P_frame\", \"B_frame\", \"P_frame\", \"P_frame\",\n                                \"B_frame\", \"I_frame\", \"B_frame\", \"P_frame\", \"I_frame\", \"P_frame\", \"I_frame\"))\ndf$frame_letter = substring(df$frame_class,1,1) # get only the beginning letter\n\n# Find the location of I_frames\nwhere_i = which(df$frame_class == \"I_frame\") \nnum_i = length(where_i)\nout_codes = list()\n\nfor (ind_i in 1:(num_i-1)){ # cycle on \"sandwiches\"\n  start = where_i[ind_i]\n  end = where_i[ind_i+1]\n  sub_data = df$frame_letter[(start+1):(end-1)]  # Get data in a sandwich\n  count_reps = rle(sub_data)  # find repetitions pattern\n\n  # build the codes\n  out_code = \"I\"\n  for (ind_letter in 1:length(count_reps$lengths)){\n    out_code= paste0(out_code, ifelse(count_reps$lengths[ind_letter] == 1, \n                     count_reps$values[ind_letter],  # If only 1 rep, don't add \"1\" in the string\n                     paste0(count_reps$lengths[ind_letter], count_reps$values[ind_letter]))) \n  }\n  out_codes [[ind_i]] = out_code # put in list\n}\nout_codes\n<\/code><\/pre>\n
, which gives: <\/p>\n
> out_codes\n[[1]]\n[1] \"I2PB2PB\"\n\n[[2]]\n[1] \"IBP\"\n\n[[3]]\n[1] \"IP\"\n<\/code><\/pre>\n
note it’s really quick and dirty: you should at least want to implement some checks to be sure that the series always start and end with an “I_frame”, but this could put you in the right direction…<\/p>\n
Also note that this could be slow for large datasets. <\/p>\n
Lorenzo<\/p>\n<\/p><\/div>\n
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            3<\/span> <\/p><\/div>\n<\/div>\n
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solved Grouping and summarizing [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Editing from previous wrong answer and borrowing from @akron for the use of rle, you can do this: assuming that your data is in a data.frame named “df” and your “frame classes” are in a column named “frame_class”, as in the code below, this should work: df = data.frame(n_frame = seq(1:13), frame_type = “frame_type”, … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[321],"class_list":["post-26187","post","type-post","status-publish","format-standard","hentry","category-solved","tag-r"],"yoast_head":"\n[Solved] Grouping and summarizing [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-grouping-and-summarizing-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Grouping and summarizing [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Editing from previous wrong answer and borrowing from @akron for the use of rle, you can do this: assuming that your data is in a data.frame named “df” and your “frame classes” are in a column named “frame_class”, as in the code below, this should work: df = data.frame(n_frame = seq(1:13), frame_type = "frame_type", ... 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