{"id":25800,"date":"2022-12-13T11:50:32","date_gmt":"2022-12-13T06:20:32","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-return-summation-of-two-lists-as-elements-in-a-new-list\/"},"modified":"2022-12-13T11:50:32","modified_gmt":"2022-12-13T06:20:32","slug":"solved-return-summation-of-two-lists-as-elements-in-a-new-list","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-return-summation-of-two-lists-as-elements-in-a-new-list\/","title":{"rendered":"[Solved] Return summation of two lists as elements in a new list"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-60134432\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"60134432\" data-parentid=\"60049019\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>I got requested result with below codes, another approach than what Marcos provided and I was able to find as well. Only additional thing is you need is to pad arrays to <code>maximum length + 1<\/code> with numpy <code>pad<\/code>.  <\/p>\n<pre><code>def elementsum2array(arr1, arr2):\n\n    '''\n    1. Make the arrays of same length padding at the beginning\/left side with 0's\n    so that arrays get the same same length of \"maximum length + 1\" (for carry at the end).\n    2. Get a new array of  length \"maximum length + 1\".\n    3. Sum the elements of the arrays from last index to first index together with carry.\n    4. Fill the new array element with sum % 10.\n    5. Update carry (sum \/\/ 10).\n    '''\n\n    if len(arr1) == 0 and len(arr2) &gt; 0:\n        return arr2\n    if len(arr1) &gt; 0 and len(arr2) == 0:\n        return arr1\n    if len(arr1) == 0 and len(arr2) == 0:\n        return []\n    else:\n        import numpy as np\n        maxlen = max(len(arr1), len(arr2))\n        arr1dif = maxlen - len(arr1) + 1\n        arr2dif = maxlen - len(arr2) + 1\n        arr1resized = np.pad(arr1, (arr1dif, 0), 'constant')\n        arr2resized = np.pad(arr2, (arr2dif, 0), 'constant')\n        L  = len(arr1resized)\n        arrnew = [0 for num in range(maxlen+1)]\n        carry = 0\n        elementsum = 0\n\n        for i in range(L-1, -1, -1):\n            elementsum = (arr1resized[i] + arr2resized[i] + carry)\n            arrnew[i] = elementsum % 10\n            #print(arrnew[i])\n            carry = elementsum \/\/ 10\n            #print(carry)\n            i=i-1\n\n    return arrnew\n\n<\/code><\/pre>\n<p>Example:<\/p>\n<pre><code>arr1 = [3,2,1,0,4,9]\narr2 =     [5,1,6,4]\nelementsum2array(arr1, arr2)\n[0, 3, 2, 6, 2, 1, 3]\n<\/code><\/pre>\n<p>This was also done in Java here:<br \/>\nsum of two arrays element wise?<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Return summation of two lists as elements in a new list <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] I got requested result with below codes, another approach than what Marcos provided and I was able to find as well. Only additional thing is you need is to pad arrays to maximum length + 1 with numpy pad. def elementsum2array(arr1, arr2): &#8221;&#8217; 1. Make the arrays of same length padding at the beginning\/left &#8230; <a title=\"[Solved] Return summation of two lists as elements in a new list\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-return-summation-of-two-lists-as-elements-in-a-new-list\/\" aria-label=\"More on [Solved] Return summation of two lists as elements in a new list\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[457,859,349],"class_list":["post-25800","post","type-post","status-publish","format-standard","hentry","category-solved","tag-algorithm","tag-data-structures","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Return summation of two lists as elements in a new list - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-return-summation-of-two-lists-as-elements-in-a-new-list\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Return summation of two lists as elements in a new list - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] I got requested result with below codes, another approach than what Marcos provided and I was able to find as well. 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