{"id":25783,"date":"2022-12-13T09:30:41","date_gmt":"2022-12-13T04:00:41","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-take-one-sample-per-row-at-a-time-compute-mean-loop-closed\/"},"modified":"2022-12-13T09:30:41","modified_gmt":"2022-12-13T04:00:41","slug":"solved-take-one-sample-per-row-at-a-time-compute-mean-loop-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-take-one-sample-per-row-at-a-time-compute-mean-loop-closed\/","title":{"rendered":"[Solved] Take one sample per row at a time, compute mean, loop [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-40391862\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"40391862\" data-parentid=\"40391561\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>First lets make so data to experiment with<\/p>\n<pre><code>set.seed(100)\nexample &lt;- matrix(runif(47*30), nrow = 47)\nexample[sample(length(example), 250)] &lt;- NA\n<\/code><\/pre>\n<p>Now we can calculate our means.  The <code>apply<\/code> function samples a random value from each row (<code>!is.na<\/code> excludes <code>NA<\/code> values), <code>mean<\/code> gets the mean, and <code>replicate<\/code> repeats this 10000 times.<\/p>\n<pre><code>exmeans &lt;- replicate(10000, mean(apply(example, 1, \n                                 function(x) sample(x[!is.na(x)], 1))))\n<\/code><\/pre>\n<p>Confidence intervals can be computed two different ways.  The first uses the example means as an empirical distribution and calculates the mean from that, the second uses a normal distribution to calculate the probablilities.<\/p>\n<pre><code>confint &lt;- quantile(exmeans, c(0.025, 0.975))\nconfint &lt;- qnorm(c(0.025, 0.975), mean = mean(exmeans), sd = sd(exmeans))\n<\/code><\/pre>\n<p>Next the plots you wanted<\/p>\n<pre><code>hist(exmeans)\nabline(v = confint, col = \"red\")\n<\/code><\/pre>\n<p><a rel=\"nofollow noopener\" target=\"_blank\" href=\"https:\/\/jassweb.com\/solved\/wp-content\/uploads\/2022\/12\/Solved-Take-one-sample-per-row-at-a-time-compute.png\"><img decoding=\"async\" src=\"https:\/\/jassweb.com\/solved\/wp-content\/uploads\/2022\/12\/Solved-Take-one-sample-per-row-at-a-time-compute.png\" alt=\"histogram of quantiles\"><\/a><\/p>\n<p>Finally the p-value information.  Once again we can eigther use an empirical distribution or a normal distribution.  These provide p-values for the lower tails of the distribution, use <code>1 - result<\/code> for upper tails.<\/p>\n<pre><code>newvalue &gt; confint[1] &amp; newvalue &lt; confint[2]\necdf(exmeans)(newvalue)\npnorm(newvalue, mean = mean(exmeans), sd = sd(exmeans))\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Take one sample per row at a time, compute mean, loop [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] First lets make so data to experiment with set.seed(100) example &lt;- matrix(runif(47*30), nrow = 47) example[sample(length(example), 250)] &lt;- NA Now we can calculate our means. The apply function samples a random value from each row (!is.na excludes NA values), mean gets the mean, and replicate repeats this 10000 times. exmeans &lt;- replicate(10000, mean(apply(example, 1, &#8230; <a title=\"[Solved] Take one sample per row at a time, compute mean, loop [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-take-one-sample-per-row-at-a-time-compute-mean-loop-closed\/\" aria-label=\"More on [Solved] Take one sample per row at a time, compute mean, loop [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1874,391,321,5308],"class_list":["post-25783","post","type-post","status-publish","format-standard","hentry","category-solved","tag-lapply","tag-loops","tag-r","tag-statistics-bootstrap"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Take one sample per row at a time, compute mean, loop [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-take-one-sample-per-row-at-a-time-compute-mean-loop-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Take one sample per row at a time, compute mean, loop [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] First lets make so data to experiment with set.seed(100) example &lt;- matrix(runif(47*30), nrow = 47) example[sample(length(example), 250)] &lt;- NA Now we can calculate our means. 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