{"id":25561,"date":"2022-12-11T02:07:34","date_gmt":"2022-12-10T20:37:34","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-java-new-object-method-why-not-be-a-error-closed\/"},"modified":"2022-12-11T02:07:34","modified_gmt":"2022-12-10T20:37:34","slug":"solved-java-new-object-method-why-not-be-a-error-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-java-new-object-method-why-not-be-a-error-closed\/","title":{"rendered":"[Solved] java new object.method() why not be a error? [closed]"},"content":{"rendered":"

[ad_1]
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the operator ‘.’ is prior than new<\/code><\/p>\n<\/blockquote>\n

No it isn’t. The operator .<\/code> is not prior to new<\/code>: they are both Primary<\/code>, so they have equal precedence, so they evaluate left to right.<\/p>\n

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why this can be executed right?<\/p>\n<\/blockquote>\n

The real question is why can it be compiled<\/em>, and I’ve answered that.<\/p>\n

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It hasn’t tell me it’s a error.<\/p>\n<\/blockquote>\n

It isn’t an error.<\/p>\n<\/p><\/div>\n

<\/div>\n<\/div>\n

0<\/span> <\/p><\/div>\n<\/div>\n

[ad_2]<\/p>\n

solved java new object.method() why not be a error? [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"

[ad_1] the operator ‘.’ is prior than new No it isn’t. The operator . is not prior to new: they are both Primary, so they have equal precedence, so they evaluate left to right. why this can be executed right? The real question is why can it be compiled, and I’ve answered that. It hasn’t … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[323],"class_list":["post-25561","post","type-post","status-publish","format-standard","hentry","category-solved","tag-java"],"yoast_head":"\n[Solved] java new object.method() why not be a error? [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-java-new-object-method-why-not-be-a-error-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] java new object.method() why not be a error? [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] the operator ‘.’ is prior than new No it isn’t. The operator . is not prior to new: they are both Primary, so they have equal precedence, so they evaluate left to right. why this can be executed right? The real question is why can it be compiled, and I’ve answered that. It hasn’t ... 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