{"id":24279,"date":"2022-12-01T20:48:18","date_gmt":"2022-12-01T15:18:18","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-get-max-value-in-a-two-value-list-python-duplicate\/"},"modified":"2022-12-01T20:48:18","modified_gmt":"2022-12-01T15:18:18","slug":"solved-get-max-value-in-a-two-value-list-python-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-get-max-value-in-a-two-value-list-python-duplicate\/","title":{"rendered":"[Solved] Get max value in a two value list Python [duplicate]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-42487569\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"42487569\" data-parentid=\"42487535\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Use the <code>max<\/code> built-in function with <code>key<\/code> kwarg. Refer to the <a rel=\"nofollow noopener\" target=\"_blank\" href=\"https:\/\/docs.python.org\/3.4\/library\/functions.html#max\">docs<\/a> of <code>max<\/code> for more details.<\/p>\n<p>It will return the sublist that has the max number, from which we take the first element (the &#8220;name&#8221;).<\/p>\n<pre><code>li = [['ABC', 1.4976557902646848], ['LMN', 1.946130694688788], ['QRS', 3.0039607941124085]]\n\nprint(max(li, key=lambda x: x[1])[0])\n# QRS\n<\/code><\/pre>\n<p>You can use <code>itemgetter<\/code> instead of defining the lambda:<\/p>\n<pre><code>from operator import itemgetter\n\nli = [['ABC', 1.4976557902646848], ['LMN', 1.946130694688788], ['QRS', 3.0039607941124085]]\n\nprint(max(li, key=itemgetter(1))[0])\n# QRS\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Get max value in a two value list Python [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Use the max built-in function with key kwarg. Refer to the docs of max for more details. It will return the sublist that has the max number, from which we take the first element (the &#8220;name&#8221;). li = [[&#8216;ABC&#8217;, 1.4976557902646848], [&#8216;LMN&#8217;, 1.946130694688788], [&#8216;QRS&#8217;, 3.0039607941124085]] print(max(li, key=lambda x: x[1])[0]) # QRS You can use itemgetter &#8230; <a title=\"[Solved] Get max value in a two value list Python [duplicate]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-get-max-value-in-a-two-value-list-python-duplicate\/\" aria-label=\"More on [Solved] Get max value in a two value list Python [duplicate]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[349],"class_list":["post-24279","post","type-post","status-publish","format-standard","hentry","category-solved","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Get max value in a two value list Python [duplicate] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-get-max-value-in-a-two-value-list-python-duplicate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Get max value in a two value list Python [duplicate] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Use the max built-in function with key kwarg. Refer to the docs of max for more details. It will return the sublist that has the max number, from which we take the first element (the &#8220;name&#8221;). li = [[&#039;ABC&#039;, 1.4976557902646848], [&#039;LMN&#039;, 1.946130694688788], [&#039;QRS&#039;, 3.0039607941124085]] print(max(li, key=lambda x: x[1])[0]) # QRS You can use itemgetter ... 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Refer to the docs of max for more details. It will return the sublist that has the max number, from which we take the first element (the &#8220;name&#8221;). li = [['ABC', 1.4976557902646848], ['LMN', 1.946130694688788], ['QRS', 3.0039607941124085]] print(max(li, key=lambda x: x[1])[0]) # QRS You can use itemgetter ... 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