{"id":24055,"date":"2022-11-30T04:05:23","date_gmt":"2022-11-29T22:35:23","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-handle-nested-list-inside-nested-dict-in-python-closed\/"},"modified":"2022-11-30T04:05:23","modified_gmt":"2022-11-29T22:35:23","slug":"solved-how-to-handle-nested-list-inside-nested-dict-in-python-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-handle-nested-list-inside-nested-dict-in-python-closed\/","title":{"rendered":"[Solved] How to handle nested list inside nested dict in Python? [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-61610622\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"61610622\" data-parentid=\"61591993\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Solution for this problem<\/p>\n<pre class=\"lang-py prettyprint-override\"><code>import json\n\ninp = {}\ncout = {}\n\n\ndef flatrn_dict(inp, name, pk_name):\n    cop_in = inp.copy()\n    pkn, pkv = identify_id(cop_in)\n    for k, v in cop_in.items():\n        if type(v) == dict:\n            if pkv is not None:\n                v.update({pkn: pkv})\n            flatrn_dict(v, k, name)\n            inp.pop(k)\n        elif type(v) == list:\n            for vx in v:\n                if pkn is not None:\n                    pkn = \"{0}_id\".format(pk_name)\n                    vx.update({pkn: pkv})\n                flatrn_dict(vx, k, name)\n            arr = cout.get(name)\n            if arr is None:\n                cout.update({name: v})\n            else:\n                arr.extend(v)\n                cout.update({name: arr})\n            inp.pop(k)\n\n\ndef identify_id(ele):\n    for k,v in ele.items():\n        if 'id' in k.lower():\n            return k, v\n    return None, None\n\nif __name__ == \"__main__\":\n    with open(\"test1.json\", \"r\") as f:\n        inp = json.load(f)\n    flatrn_dict(inp, \"prop\", \"\")\n    with open(\"test_out.json\", \"w\") as fw:\n        fw.write(json.dumps(cout))\n\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to handle nested list inside nested dict in Python? [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Solution for this problem import json inp = {} cout = {} def flatrn_dict(inp, name, pk_name): cop_in = inp.copy() pkn, pkv = identify_id(cop_in) for k, v in cop_in.items(): if type(v) == dict: if pkv is not None: v.update({pkn: pkv}) flatrn_dict(v, k, name) inp.pop(k) elif type(v) == list: for vx in v: if pkn is &#8230; <a title=\"[Solved] How to handle nested list inside nested dict in Python? [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-handle-nested-list-inside-nested-dict-in-python-closed\/\" aria-label=\"More on [Solved] How to handle nested list inside nested dict in Python? [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[349],"class_list":["post-24055","post","type-post","status-publish","format-standard","hentry","category-solved","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>[Solved] How to handle nested list inside nested dict in Python? [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-handle-nested-list-inside-nested-dict-in-python-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to handle nested list inside nested dict in Python? [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Solution for this problem import json inp = {} cout = {} def flatrn_dict(inp, name, pk_name): cop_in = inp.copy() pkn, pkv = identify_id(cop_in) for k, v in cop_in.items(): if type(v) == dict: if pkv is not None: v.update({pkn: pkv}) flatrn_dict(v, k, name) inp.pop(k) elif type(v) == list: for vx in v: if pkn is ... 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