{"id":23873,"date":"2022-11-28T22:08:22","date_gmt":"2022-11-28T16:38:22","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-get-data-from-url-in-php-duplicate\/"},"modified":"2022-11-28T22:08:22","modified_gmt":"2022-11-28T16:38:22","slug":"solved-get-data-from-url-in-php-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-get-data-from-url-in-php-duplicate\/","title":{"rendered":"[Solved] Get data from url in php [duplicate]"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

\n
\n
<\/div>\n
\n
\n

If you have a $url<\/p>\n

$url = \"http:\/\/example.com\/file\/vars.txt\";<\/code><\/p>\n

and want to display on-screen text “Filename: vars.txt” then you can use the code below to do that<\/p>\n

$filename = basename($url);\necho \"Filename $filename\";\n<\/code><\/pre>\n
Edited Answer:<\/p>\n
What you are trying to do is potentially quite dangerous as anyone can select any file from your server to include in your page and get your website hacked, to make this a bit more secure you can do the following<\/p>\n
<?php\n$files = array(\n   \"vars\" => \"vars.txt\",\n   \"vars2\" => \"vars2.txt\",\n   \"some-other-file\" => \"vars3.txt\"\n); \n\nif( $_GET['p'] && isset( $files[ $_GET['p'] ] ) {\n    echo file_get_contents( $files[ $_GET['p'] ] );\n}\n?>\n<\/code><\/pre>\n
Then when you enter an URL like http:\/\/example.com\/?p=vars<\/a> then vars.txt content will be print on the screen.<\/p>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            5<\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved Get data from url in php [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] If you have a $url $url = “http:\/\/example.com\/file\/vars.txt”; and want to display on-screen text “Filename: vars.txt” then you can use the code below to do that $filename = basename($url); echo “Filename $filename”; Edited Answer: What you are trying to do is potentially quite dangerous as anyone can select any file from your server to … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1280,339],"class_list":["post-23873","post","type-post","status-publish","format-standard","hentry","category-solved","tag-get","tag-php"],"yoast_head":"\n[Solved] Get data from url in php [duplicate] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-get-data-from-url-in-php-duplicate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Get data from url in php [duplicate] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] If you have a $url $url = "http:\/\/example.com\/file\/vars.txt"; and want to display on-screen text “Filename: vars.txt” then you can use the code below to do that $filename = basename($url); echo "Filename $filename"; Edited Answer: What you are trying to do is potentially quite dangerous as anyone can select any file from your server to ... 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