{"id":23339,"date":"2022-11-25T10:40:28","date_gmt":"2022-11-25T05:10:28","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-difference-between-dates-concatenated-together\/"},"modified":"2022-11-25T10:40:28","modified_gmt":"2022-11-25T05:10:28","slug":"solved-difference-between-dates-concatenated-together","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-difference-between-dates-concatenated-together\/","title":{"rendered":"[Solved] difference between dates concatenated together"},"content":{"rendered":"

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Picture paints a thousand words<\/p>\n<\/blockquote>\n

No! Don’t post pictures of data or code!<\/p>\n

Your question is not at all clear, even with the picture. And – looking at my attempt to answer – you see, that I had to type in a test scenario. This was your job actually… For the next question please provide a working stand-alone<\/em> scenario and add the expected output. Add the code you tried yourself and some explanation. This is worth a thousand words<\/em>, pictures are annoying…<\/p>\n

As told already: The question is not very clear, so this might be wrong for you, but my magic crystal ball tells me, that you are looking for this:<\/p>\n

DECLARE @tbl TABLE(D1 DATE, D2 DATE);\n\nINSERT INTO @tbl VALUES\n ({d'2016-02-01'},{d'2016-03-31'})\n,({d'2015-10-01'},{d'2016-01-31'})  --Your Row 2\n,({d'2016-09-01'},{d'2016-10-31'})  --Your Row 4\n,({d'2015-12-01'},{d'2015-12-31'})\n,({d'2018-04-01'},{d'2018-06-30'})\n,({d'2018-04-04'},{d'2018-06-30'})  --Day index != 1, but smaller in D1\n,({d'2018-04-04'},{d'2018-06-03'}); --Day index is smaller in D2\n\nSELECT t.*\n      ,A.CountOfMonths\n      ,(\n         SELECT TOP(A.CountOfMonths) CONCAT(' '\n                                           ,FORMAT(DATEADD(MONTH,ROW_NUMBER() OVER(ORDER BY (SELECT NULL))-1,D1),'MMyy')\n                                           ) \n         FROM master..spt_values\n         FOR XML PATH('')\n       )\nFROM @tbl t\nCROSS APPLY (SELECT DATEDIFF(MONTH,D1,D2)\n                    + CASE WHEN DAY(D1)<DAY(D2) THEN 1 ELSE 0 END) A(CountOfMonths);\n<\/code><\/pre>\n
The result<\/p>\n
D1          D2         CoM   \n2016-02-01  2016-03-31  2    0216 0316\n2015-10-01  2016-01-31  4    1015 1115 1215 0116\n2016-09-01  2016-10-31  2    0916 1016\n2015-12-01  2015-12-31  1    1215\n2018-04-01  2018-06-30  3    0418 0518 0618\n2018-04-04  2018-06-30  3    0418 0518 0618\n2018-04-04  2018-06-03  2    0418 0518\n<\/code><\/pre>\n
The query will use some calculation to find the “NumberOfMonths” between the two dates. This value will be used to get the TOP()<\/code> rows of a table. I use master..spt_values<\/code> which is just a table with many rows. We are not interested in these values, just in a result set with the correct count of rows. On this set I apply ROW_NUMBER<\/code> to get a running number (1,2 or 1,2,3,4 and so on). This running number is added in months to D1. The final output is done by FORMAT()<\/code>.<\/p>\n
The row with the 4th of April shows, that your first date is not always the first of the month. So I added a case where the day’s index of the second month is smaller and I use a CASE<\/code> to add one more month in “normal” situations. Might be, that you want to change this to <=<\/code>… I don’t know what you want to happen if the day’s index is the same in D1 and D2…<\/p>\n
If this does not solve your problem please use my scenario, add explanatory data and use the edit option of your question to make a good question out of it…<\/p>\n<\/p><\/div>\n
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            1<\/span> <\/p><\/div>\n<\/div>\n
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solved difference between dates concatenated together <\/p>\n","protected":false},"excerpt":{"rendered":"
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